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    Anyone know how to solve
    |x+1| is more than or equal to -3?
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    For all values of x.

    The easiest way to do so is to draw a graph of f(x) = mod (x+1) and of f(x) = -3 and see that for all values of x, mod(x+1) is greater than -3.

    Are you sure you don't mean +3?
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    The actual qn is
    -3<=|x+1|<=1
    Ans: -1<x<=0 and -2<=x<-1
 
 
 
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