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# Math watch

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1. Anyone know how to solve
|x+1| is more than or equal to -3?
2. For all values of x.

The easiest way to do so is to draw a graph of f(x) = mod (x+1) and of f(x) = -3 and see that for all values of x, mod(x+1) is greater than -3.

Are you sure you don't mean +3?
3. The actual qn is
-3<=|x+1|<=1
Ans: -1<x<=0 and -2<=x<-1

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Updated: November 6, 2015
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