At what altitude h above the North Pole is the weight of an object reduced to one half its value on the Earth’s surface? Assume the Earth to be a sphere radius R and express h as a fraction of R.
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runny4
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- 06-11-2015 19:12
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16Characters....
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- 06-11-2015 19:15
(Original post by runny4)
At what altitude h above the North Pole is the weight of an object reduced to one half its value on the Earth’s surface? Assume the Earth to be a sphere radius R and express h as a fraction of R. -
Absent Agent
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- 06-11-2015 19:18
(Original post by runny4)
At what altitude h above the North Pole is the weight of an object reduced to one half its value on the Earth’s surface? Assume the Earth to be a sphere radius R and express h as a fraction of R. -
runny4
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- 06-11-2015 21:54
(Original post by 16Characters....)
The weight of an object is inversely proportional to the square of the distance between that object and the centre of the Earth. Use ratios therefore to find (R+h) in terms of R. -
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- 06-11-2015 22:01
(Original post by runny4)
so ive got that the height must be root 2 times r but then what do u do? -
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- 06-11-2015 22:03
that's a really hard question i have to admit- this is probably no help to u at all
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runny4
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- 08-11-2015 12:07
(Original post by 16Characters....)
The height and the distance from the centre of the Earth are not the same since we measure height from the Earth's surface, not the centre -
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- 08-11-2015 12:17
(Original post by runny4)
so what is h and why?so
Last edited by EricPiphany; 08-11-2015 at 12:20. -
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- 08-11-2015 15:29
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