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# Is there a better way to solev this? watch

1. ..
2. (Original post by MCPC247)
Find all real numbers x, y and z which satisfy the simultaneous equations x^2 − 4y + 7 = 0, y^2 − 6z + 14 = 0 and z^2 − 2x − 7 = 0.
I got a solution through a really long method, followed by inspection. Is there a nicer way to do it?
This has come up recently on the maths forum (always best to post there, rather than this umbrella forum).

Add the three equations together and complete the squares. There is only one solution, which should now be obvious.

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Updated: November 7, 2015
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