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    I am stuck on part iv on q10. What I don't understand is why you have to equate the gradients of the line and curve?
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    (Original post by danbomb123)
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    I am stuck on part iv on q10. What I don't understand is why you have to equate the gradients of the line and curve?
    Think about any curve and a tangent at any point, and what the tangent actually is.

    A tangent to a curve at any point is a line passing through the same point with the same gradient as the curve at that point.
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    (Original post by SeanFM)
    Think about any curve and a tangent at any point, and what the tangent actually is.

    A tangent to a curve at any point is a line passing through the same point with the same gradient as the curve at that point.
    How come equating the equation of the curve and line will not get the answer?
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    (Original post by danbomb123)
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    I am stuck on part iv on q10. What I don't understand is why you have to equate the gradients of the line and curve?
    at (p,q), the gradient of the tangent and the gradient of the line are equal so if you equate the gradient functions (dy/dx) of each one, you can solve it for x (p). by substituting this x value into either the tangent or the line equation, you can find out the y co-ordinate(q)
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    (Original post by danbomb123)
    How come equating the curve and line will not get the answer?
    I would have hoped that it did, unless we are missing something, and that's the approach I would've taken rather than finding gradients.
 
 
 
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