x Turn on thread page Beta
 You are Here: Home >< Maths

# Maths AS question (Curves) watch

1. I worked out Q(a) but not sure about (b). I got -x^2-2cx+c for part a; I might be wrong though but I assume you just expand the brackets and make it in that form. Thanks in advance!

Posted from TSR Mobile
2. This is not the answer, but your handwriting is amazing - do you use parker pens/expensive pens?
3. (Original post by KK.Violinist)

I worked out Q(a) but not sure about (b). I got -x^2-2cx+c for part a; I might be wrong though but I assume you just expand the brackets and make it in that form. Thanks in advance!

Posted from TSR Mobile
Your part (a) is slightly incorrect, you have (note the square of the ) - now just distribute the sign into the brackets.
4. Work out all the letters in the equations then find B with making f(X) = g(X). C is the X intercept of h(X) so that should be easy and then length from that.
5. (Original post by KK.Violinist)

I worked out Q(a) but not sure about (b). I got -x^2-2cx+c for part a; I might be wrong though but I assume you just expand the brackets and make it in that form. Thanks in advance!

Posted from TSR Mobile
Note that gradient of line 1 - can you then write down the equation of line 1 (you know where it intersects the y-axis as well) and find where it intersects ? What about finding where and intersect and then can you use to find the gradient of ?
6. (Original post by TheYearNiner)
This is not the answer, but your handwriting is amazing - do you use parker pens/expensive pens?
Thanks haha, I use a standard ballpoint pen.

Posted from TSR Mobile
7. (Original post by Zacken)
Note that gradient of line 1 - can you then write down the equation of line 1 (you know where it intersects the y-axis as well) and find where it intersects ? What about finding where and intersect and then can you use to find the gradient of ?
Sorry, my minds gone blank. How would I go about finding the equation of line 1? y=mx+c where -8 is c and mx being f'(x)?

Posted from TSR Mobile
8. (Original post by KK.Violinist)
Sorry, my minds gone blank. How would I go about finding the equation of line 1? y=mx+c where -8 is c and mx being f'(x)?

Posted from TSR Mobile
Differentiate, sub in the x value of the coordinate of the point given which lies on line to get the gradient; and use y-y1 =m(x-x1).

Your handwriting is so damn good, it makes me feel like a toddler
9. (Original post by kkboyk)
Differentiate, sub in the x value of the coordinate of the point given which lies on line to get the gradient; and use y-y1 =m(x-x1).

Your handwriting is so damn good, it makes me feel like a toddler
Okay, if my calculations are correct then the line is y=2x-8.

Why is everyone talking about my handwriting!!! Haha I think it's pretty average, I've seen classmates with better handwriting xD

Posted from TSR Mobile
10. (Original post by KK.Violinist)
Okay, if my calculations are correct then the line is y=2x-8.

Why is everyone talking about my handwriting!!! Haha I think it's pretty average, I've seen classmates with better handwriting xD

Posted from TSR Mobile
Because most people doing Maths (especially university Maths students and Professors) have terrible handwriting.

I sometimes can't read my own handwriting
11. (Original post by kkboyk)
Because most people doing Maths (especially university Maths students and Professors) have terrible handwriting.

I sometimes can't read my own handwriting
Lol that's true but surprisingly my teacher has very neat handwriting that makes even mine look mediocre.

Anyway, back on topic, now I have to find point A? I really shouldn't be doing this so late during the night. My brain keeps switching off -_-

Posted from TSR Mobile
12. (Original post by KK.Violinist)
Lol that's true but surprisingly my teacher has very neat handwriting that makes even mine look mediocre.

Anyway, back on topic, now I have to find point A? I really shouldn't be doing this so late during the night. My brain keeps switching off -_-

Posted from TSR Mobile
Simultaneous equations with line L1 and g(x).
13. (Original post by kkboyk)
Simultaneous equations with line L1 and g(x).
I'm slightly confused by the D. I found D=40 but not sure if I'm correct. Do I even need to find D? Sorry for my amateur replies

Posted from TSR Mobile
14. (Original post by KK.Violinist)
I'm slightly confused by the D. I found D=40 but not sure if I'm correct. Do I even need to find D? Sorry for my amateur replies

Posted from TSR Mobile
What is D?
15. (Original post by kkboyk)
What is D?
g(x)=x^2-14x+D

Posted from TSR Mobile
16. (Original post by KK.Violinist)
g(x)=x^2-14x+D

Posted from TSR Mobile
Oh its a constant.

If you differentiate g(x) and also L1 make them equal to each other (as they both will have the same gradient at that point) you'll be able to find the x value
17. (Original post by kkboyk)
Oh its a constant.

If you differentiate g(x) and also L1 make them equal to each other (as they both will have the same gradient at that point) you'll be able to find the x value
So find the second derivative for f(x) and the first for g(x) and equal to each other? If so then I got x=8

Posted from TSR Mobile

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: November 8, 2015
Today on TSR

### Complete university guide 2019 rankings

Find out the top ten here

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams