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    Why is there not an answer to this? (-64)^3=4(16)^(2/3)x

    I did 3 = -3/2x
    3x-2/3 = x
    x = -2
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    (Original post by Airess3)
    Why is there not an answer to this? (-64)^3=4(16)^(2/3)x

    I did 3 = -3/2x
    3x-2/3 = x
    x = -2
    First off, you'd be better off posting straight into the Maths forum.

    It looks like you've tried to equate 4(16)^{\frac{2}{3}x} to 64^{\frac{2}{3}x} which is just not true.
    I am, however, puzzled as to where you pulled the \dfrac{-3}{2}x from.
    Could you be a little clearer about what you've done?

    Finally, it is not true that this has no solution, only that there is no real solution. A complex solution does exist.
 
 
 
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