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What are the coordinates of the point where the graph of y=log (subscript 7) (x)+1? watch

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    So I know I'm trying to find where y=0 so I'm doing 7^(x+1)=0. But I don't know how to find x. I tried converting it to log (subscript 7) (0)=x+1. But still don't can't find x once I made it log (subscript 7) (-1).
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    (Original post by Airess3)
    So I know I'm trying to find where y=0 so I'm doing 7^(x+1)=0. But I don't know how to find x. I tried converting it to log (subscript 7) (0)=x+1. But still don't can't find x once I made it log (subscript 7) (-1).
    No solutions.  7^{x+1} > 0, \forall x \in \mathbb{R}
 
 
 
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