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    1.65g Mn and0.64g of O to make manganese oxide. The number of moles of Mn is 0.03 and the number of moles for O is 0.04. If I then divide both numbers by 0.03, you get 1.3 recurring for O? Should I just multiply the amount of moles by 100 to get Mn3O4?

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    (Original post by Megan_101)
    1.65g Mn and0.64g of O to make manganese oxide. The number of moles of Mn is 0.03 and the number of moles for O is 0.04. If I then divide both numbers by 0.03, you get 1.3 recurring for O? Should I just multiply the amount of moles by 100 to get Mn3O4?

    Thanks
    yes, you must multiply through by an appropriate number to make all of the other numbers integral.
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    (Original post by charco)
    yes, you must multiply through by an appropriate number to make all of the other numbers integral.
    Thank you
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    (Original post by charco)
    yes, you must multiply through by an appropriate number to make all of the other numbers integral.
    Do you have any idea how to do this question?
    Calculate the number of moles of atoms (gram-atoms) of the elements combining with 1 mole of atoms (gram-atoms) of oxygen and hence deduce the the formula of the oxide of 0.69g of sodium formed 0.93g of sodium oxide? Thanks
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    (Original post by Megan_101)
    Do you have any idea how to do this question?
    Calculate the number of moles of atoms (gram-atoms) of the elements combining with 1 mole of atoms (gram-atoms) of oxygen and hence deduce the the formula of the oxide of 0.69g of sodium formed 0.93g of sodium oxide? Thanks
    divide sodium by its relative atomic mass
    divide the difference between the mass of sodium and the mass of sodium oxide by the relative atomic mass of oxygen
    Simplify the ratio.
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    (Original post by charco)
    divide sodium by its relative atomic mass
    divide the difference between the mass of sodium and the mass of sodium oxide by the relative atomic mass of oxygen
    Simplify the ratio.
    Thank you so much
 
 
 
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