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Really stuck. Complex numbers, z, argument watch

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    Find some equation for z whose solution is set to y=5x-2

    The answer is Im((1-5j)z)

    And z is X+ij
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    (Original post by Doodles12345)
    Find some equation for z whose solution is set to y=5x-2

    The answer is Im((1-5j)z)

    And z is X+ij
    Can you post the full question?
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    (Original post by Zacken)
    Can you post the full question?
    Unfortunately that is the whole question
    My tutor said something about working backwards by expressing arg(X+iy)(a+bi)=c in terms or X and y and then comparing a b and c to the solution, but I didn't understand how to do that
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    (Original post by Doodles12345)
    Unfortunately that is the whole question
    My tutor said something about working backwards by expressing arg(X+iy)(a+bi)=c in terms or X and y and then comparing a b and c to the solution, but I didn't understand how to do that
    please post a photo of the question.
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    Try (x+ij)(a+bi) = 5x-2

    Seperate the real and imaginary parts after expanding and you should get your answer
 
 
 
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Updated: November 13, 2015
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