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    did anybody else do this paper. the calculator paper 6 was yesterday. It was the one with the circle of x2+y2=13 and A and B were on the line y=2x-1 and met both lines. It was 7 marks

    how did others find the paper
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    I did that paper, i found it quite easy, the question you metioned about the circles was like this,

    1 Y^2 + x^2 = 13
    2 y = 2x - 1

    rearrange 1. y^2 = 13 - x^2
    square 2. y^2 = (2x - 1)^2
    y^2 = 4x^2 -4x +1

    13 - x^2 = 4x^2 - 4x +1
    5x^2 - 4x - 12 = 0
    Factorize (5x +6)(x - 2) = 0

    x = -1.2 or 2

    so y = -3.4 or 3

    A = (2,3)
    B = (-1.2,-3.4)
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    (Original post by mrjoe)
    I did that paper, i found it quite easy, the question you metioned about the circles was like this,

    1 Y^2 + x^2 = 13
    2 y = 2x - 1

    rearrange 1. y^2 = 13 - x^2
    square 2. y^2 = (2x - 1)^2
    y^2 = 4x^2 -4x +1

    13 - x^2 = 4x^2 - 4x +1
    5x^2 - 4x - 12 = 0
    Factorize (5x +6)(x - 2) = 0

    x = -1.2 or 2

    so y = -3.4 or 3

    A = (2,3)
    B = (-1.2,-3.4)
    yay that's what i got
    Cacked myself though when i saw a circular graph and then saw that it was worth 7 marks!
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    That was a bit excessive for one question, but good if you could do a simple substitution.

    They haven't examined transformations, rotation etc. in about 4 years!
 
 
 

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