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Finding change in internal energy with different heat absorbency values?

When a reaction is run at constant volume 9.19 kJ of heat was absorbed: when run atconstant pressure, 8.62 kJ is absorbed. What is ∆U for the reaction

I know that q= enthalpy at constant pressure and i know that makes it relate in some way but i don't know what equation to use, any help would be great, thanks!
∆U = ∆q at constant volume, since dU = dq + dW = dQ - pdV assuming only expansion work

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