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Voltage across Capacitor equation derivation. Pls help, much appreciated
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You will get the exact same formula even if you do not multiply by -1. I think it might be because it makes the LHS integral a tiny bit nicer (though it really makes no difference in my opinion):
Now is probably the time where a physicist comes in an tells me it is not as simple as the maths suggests haha.
Now is probably the time where a physicist comes in an tells me it is not as simple as the maths suggests haha.
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(Original post by 16Characters....)
You will get the exact same formula even if you do not multiply by -1. I think it might be because it makes the LHS integral a tiny bit nicer (though it really makes no difference in my opinion):
Now is probably the time where a physicist comes in an tells me it is not as simple as the maths suggests haha.
You will get the exact same formula even if you do not multiply by -1. I think it might be because it makes the LHS integral a tiny bit nicer (though it really makes no difference in my opinion):
Now is probably the time where a physicist comes in an tells me it is not as simple as the maths suggests haha.
The equation tells us the charge stored in an initially isolated capacitor (Vc = Vo) will exponentially decay at a rate governed by the product between the capacitance and current path resistance.
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