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M3 OCR answers watch

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    Just done the test, thought it was nice and kind. Anyways MY answers...

    1. Impulse = 11.2Ns

    2. theta = 60degrees

    V = 5.20m/s (it was 3root3 i think)

    e = 1/6

    3. i got x = 1/2k ln (g+kv^2/g)

    4. Prove SHM. T = 7.18s , t between 0.06 and -0.06 = 1.47s

    5. use f=ma to prove max v when length = 14 (max v when a = 0)

    next part use energy equations to show that vmax = 26.9m/s

    6. Bhoriz = 45N
    Bvert = 10N

    didn't get mew as i ran out of time!!

    7. u = root(ag)
    theta = 1.91
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    (Original post by jonas123)
    Just done the test, thought it was nice and kind. Anyways MY answers...

    1. Impulse = 11.2Ns

    2. theta = 60degrees

    V = 5.20m/s (it was 3root3 i think)

    e = 1/6

    3. i got x = 1/2k ln (g+kv^2/g)

    4. Prove SHM. T = 7.18s , t between 0.06 and -0.06 = 1.47s

    5. use f=ma to prove max v when length = 14 (max v when a = 0)

    next part use energy equations to show that vmax = 26.9m/s

    6. Bhoriz = 45N
    Bvert = 10N

    didn't get mew as i ran out of time!!

    7. u = root(ag)
    theta = 1.91
    I agree with all but 6, that is they don't look wrong to me. Also I didn't do the last part of 7, I was checking it at the end, realised I done it wrong, but didn't have time to finish it. With 6 someone else disagreed with me, so perhaps I'm wrong :mad:.
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    a few got the same as me for 6.

    the last part of 7 was cos^-1 (-1/3) =1.91
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    I got everything but your answer to 1 which I got something else I think. I suspect I'm wrong.

    Was it me or was this a shockingly easy paper? I'm worried that I found it so easy.

    Also, the question where you had to show the maximum velocity was at 44m, did anybody do this using implicit differentiation of a v-x function derived from the problem? I got the answer this way but thought the method was bizarre!
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    Can anybody recall question 1?
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    I can't remember q1, the OP may be wrong or right. No, differnetiation was not necessary, what you needed to do was recognise acceleration would occur while mg>kx (k is lambda/l).
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    (Original post by Jojoba86)
    I can't remember q1, the OP may be wrong or right. No, differnetiation was not necessary, what you needed to do was recognise acceleration would occur while mg>kx (k is lambda/l).
    Oh I'm sure it wasn't necessary. But I hope I will still get the marks, since my energy equations were still correct.
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    I expect you should, one of my mates done the same!
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    question1 was the cricket bat one.

    initial velo = 20m/s
    final velo = 32m/s at angle 60degrees to initial delivery

    find magnitude of impulse (mass was 0.4kg)
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    Doh. Misread the question. That's my 100% gone then =P
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    so... i got the impulse as 28 because i forgot to x by mass :'(! ummm the statics q'n i only just got at the end so quickly scribbled stuff down but got the answers, am I likely to get full marks without complete method - diagram etc?? and d'oh! easy paper but i messed up a bit - nevermind should still get my a if s2 and m2 go ok
 
 
 
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