Original post by pineneedles
I don't know what to do for part e) on this question:
"Write down" implies little or no working is required.
Consider your answer to part d. What part of the curve did that represent?
Hence what part of the curve is left? And its equation will be?
Original post by ghostwalker
"Write down" implies little or no working is required.
Consider your answer to part d. What part of the curve did that represent?
Hence what part of the curve is left? And its equation will be?
Consider your answer to part d. What part of the curve did that represent?
Hence what part of the curve is left? And its equation will be?
Part B represents the part of the curve where x is greater than or equal to zero, so the part left is where x is less than or equal to zero. I think it should have the same equation therefore but be a reflection in the y axis. Would the equation be
-2xsqrt(1+x^2)?
Original post by pineneedles
Part B represents the part of the curve where x is greater than or equal to zero
Part d, and try again. What values does x take when t varies from 0 to pi?
Edit: Your answer is actually correct, but your reasoning isn't.
(edited 8 years ago)
Original post by pineneedles
...
I've shaded the graph represented by part d in the attachment.
Original post by ghostwalker
Part d, and try again. What values does x take when t varies from 0 to pi?
Edit: Your answer is actually correct, but your reasoning isn't.
Edit: Your answer is actually correct, but your reasoning isn't.
I struggle getting my head around this. So x goes from -1 to 1 when t varies from 0 to pi. This part of the curve must be above the x axis. Rather than being a reflection in the y axis it's a reflection in the x axis.Original post by pineneedles I struggle getting my head around this. So x goes from -1 to 1 when t varies from 0 to pi. This part of the curve must be above the x axis. Rather than being a reflection in the y axis it's a reflection in the x axis.
I struggle getting my head around this. So x goes from -1 to 1 when t varies from 0 to pi. This part of the curve must be above the x axis. Rather than being a reflection in the y axis it's a reflection in the x axis.Yes, it is a reflection in the x-axis. See my last post.
As t goes from 0 to pi/2, both x and y are postive, so top right quadrant.
As t goes from pi/2 to p, x and y are negative, so bottom left quadrant.
Original post by ghostwalker
Yes, it is a reflection in the x-axis. See my last post.
As t goes from 0 to pi/2, both x and y are postive, so top right quadrant.
As t goes from pi/2 to p, x and y are negative, so bottom left quadrant.
As t goes from 0 to pi/2, both x and y are postive, so top right quadrant.
As t goes from pi/2 to p, x and y are negative, so bottom left quadrant.
Got it, thank you
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