Chemstry help-whats atom economy and percentage yieldWatch
What are advantages for sustainability of processes with high atom economy
I'm going to quote in Tank Girl now so she can move your thread to the right place if it's needed.
- measures efficiency of an equation / how many atoms are lost / how wasteful, so how green it is
molar mass of desired product / molar mass of all reagents x 100% = ... %
find moles of a reagent
convert figure if need be, from ratio 1:2 double 2:1 half, 1:3 triple and so on and so forth
find mass of product (whose actual mass you know)
this is your theoretical maximum mass
then calculated by:
actual mass / theoretical maximum mass x 100% = ... %
In A2 you are required to manipulate that equation to a degree.
So rearrange / do backwards etc etc.
Edit: when saying what atom economy is for, these might not be model / markscheme answers.
% atom economy = Mr of desired product / Mr of reagents x 100%
1) n = m / Mr, n = c x v (in dm3, so /1000 if in cm3)
Find moles of a reagent
2) In the ratio, multiply/divide so that the first number in the ratio equals the second number.
A ratio of 1:2, you must double.
3) m = n x Mr
Find mass of a product (whose mass which is produced you know) = theoretical maximum mass
Then % yield = actual mass / theoretical maximum mass x 100%