The Student Room Group

sketch y=(x-1)^3-4(x-1)

?? so confused about this question and its only 3 marks

need guidance plz

sketch y=(x-1)^3-4(x-1)
Original post by SuperHuman98
?? so confused about this question and its only 3 marks

need guidance plz

sketch y=(x-1)^3-4(x-1)


First, factorise.
Original post by BuryMathsTutor
First, factorise.


it is already factorised
Original post by SuperHuman98
it is already factorised
.

(x1)(a quadratic)(x-1)(\text{a quadratic}) then factorise a little more.
Original post by SuperHuman98
?? so confused about this question and its only 3 marks

need guidance plz

sketch y=(x-1)^3-4(x-1)


Factorise.

Where does this graph cross the axes?

You know the shape of a positive cubic. There you go.

If you really want to, you can differentiate and find the max and the min too.
Original post by BuryMathsTutor
.

(x1)(a quadratic)(x-1)(\text{a quadratic}) then factorise a little more.


Original post by Mr M
Factorise.

Where does this graph cross the axes?

You know the shape of a positive cubic. There you go.

If you really want to, you can differentiate and find the max and the min too.


I cant figure out how to factrorise this, do I need to expand everything first?
Original post by SuperHuman98
I cant figure out how to factrorise this, do I need to expand everything first?


Take out the common factor of (x-1).
Reply 7
By the way (x1)(...)(x-1)(...) where the ... inside will be a difference of two squares and easy to factorise.
Original post by Zacken
By the way (x1)(...)(x-1)(...) where the ... inside will be a difference of two squares and easy to factorise.


Original post by Mr M
Take out the common factor of (x-1).


I have got x(x-1)(x+1)-4(x-1)=o
Original post by SuperHuman98
I have got x(x-1)(x+1)-4(x-1)=o


You need to revise factorising.

y=(x1)34(x1)y=(x-1)^3-4(x-1)

y=(x1)((x1)24)y=(x-1)((x-1)^2-4)

y=(x1)(x3)(x+1)y=(x-1)(x-3)(x+1)
you could work with

y = x3 - 4x

and apply a suitable translation

Quick Reply

Latest