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Stuck on simple formula rearranging
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andyuser727
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#1
Hi
I'd be very grateful for any help. The question I'm trying to answer says :-
Rearrange the formula p(q-1) = q to make q the new subject.
The answer given is q = p/(p-1)
I don't understand how you get this answer...
Can anyone show the working please?
Thanks
I'd be very grateful for any help. The question I'm trying to answer says :-
Rearrange the formula p(q-1) = q to make q the new subject.
The answer given is q = p/(p-1)
I don't understand how you get this answer...
Can anyone show the working please?
Thanks
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Notnek
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#2
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#2
(Original post by andyuser727)
Hi
I'd be very grateful for any help. The question I'm trying to answer says :-
Rearrange the formula p(q-1) = q to make q the new subject.
The answer given is q = p/(p-1)
I don't understand how you get this answer...
Can anyone show the working please?
Thanks
Hi
I'd be very grateful for any help. The question I'm trying to answer says :-
Rearrange the formula p(q-1) = q to make q the new subject.
The answer given is q = p/(p-1)
I don't understand how you get this answer...
Can anyone show the working please?
Thanks
Have a go at this and post all your working if you get stuck.
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andyuser727
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#3
pq - p = q
pq - q = p
q(q - 1) = p
q = p / (q - 1)
OK excellent! Thanks. I still have questions tho. If you start substituting values for p and q, the formula looks wrong.
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
pq - q = p
q(q - 1) = p
q = p / (q - 1)
OK excellent! Thanks. I still have questions tho. If you start substituting values for p and q, the formula looks wrong.
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
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Duke Glacia
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#4
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#4
(Original post by andyuser727)
pq - p = q
pq - q = p
q(q - 1) = p
q = p / (q - 1)
OK excellent! Thanks. I still have questions tho. If you start substituting values for p and q, the formula looks wrong.
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
pq - p = q
pq - q = p
q(q - 1) = p
q = p / (q - 1)
OK excellent! Thanks. I still have questions tho. If you start substituting values for p and q, the formula looks wrong.
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
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Notnek
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#5
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#5
OK excellent! Thanks. I still have questions tho. If you start substituting values for p and q, the formula looks wrong.
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
Eg. p = 2, q = 3
2(3 - 1) = 3
6 - 2 = 3
4 = 3 ?????
If you're still not clear about this, please explain exactly what you mean.
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andyuser727
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#6
pq - p = q
pq - q = p
q(p - 1) = p
q = p/(p - 1)
oops, sorry. Is that correct now?
I don't know why I was substituting random values. I get it now.
So if p = 3 then
q = 3/(3 - 1) then
q = 3/2
q = 1.5
pq - q = p
q(p - 1) = p
q = p/(p - 1)
oops, sorry. Is that correct now?
I don't know why I was substituting random values. I get it now.
So if p = 3 then
q = 3/(3 - 1) then
q = 3/2
q = 1.5
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Notnek
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#7
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#7
(Original post by andyuser727)
pq - p = q
pq - q = p
q(p - 1) = p
q = p/(p - 1)
oops, sorry. Is that correct now?
I don't know why I was substituting random values. I get it now.
So if p = 3 then
q = 3/(3 - 1) then
q = 1 2/3
pq - p = q
pq - q = p
q(p - 1) = p
q = p/(p - 1)
oops, sorry. Is that correct now?
I don't know why I was substituting random values. I get it now.
So if p = 3 then
q = 3/(3 - 1) then
q = 1 2/3
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