P2 Modulus

if u have a modulus expression say

l 3x+5 l = l 5x l

do you have to square both sides to solve, or do you just treat the mod bit as brackets


or wqhat if you have one\side with a modulus bit
eg solve for x, in terms of a:
3a = l x-(4x+a) l +a

i get x= 2a(1-a)/(1-4a)

could someone post some more examples with solutions of different types of mod equation questions

if u have a modulus expression say

l 3x+5 l = l 5x l

do you have to square both sides to solve, or do you just treat the mod bit as brackets


or wqhat if you have one\side with a modulus bit
eg solve for x, in terms of a:
3a = l x-(4x+a) l +a

i get x= 2a(1-a)/(1-4a)

could someone post some more examples with solutions of different types of mod equation questions

² ³ ± ÷ ° √ ∂ ∞ ≈ ≠ ≡ ≥ ≤ ø Ø ½ ¼ « » µ π


3a = l x-(4x+a) l +a
2a = l x-(4x+a) l
±2a = x-(4x+a) therefore:

3a+3x=0
OR
-a+3x=0

I don't understand the ±2 in the bold bit??? Where did that come from

The modulus can be switched, e.g.

a = l x l is the same as saying:
±a = x

ahh - i see! thanks!!!

Though in the case of:

l a l = l x l you can't do it.