Louisb19
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#1
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#1
https://gyazo.com/bb72d5f49c5d646c63e28f4c52b7874a
https://gyazo.com/f975cdafca7192393382e04ccac48be7

The solution to this question isn't making much sense to me. I found the following:

 | \vec{AD} | = 2l + x_1 + x_2

 l = 2 x_1 + 4 x_2

In the solution they act as if  x_1 is going to be the same if the second spring was not there. It was my understanding that since:

 mg = T_1 + T_2

If the second string was removed (such that the weight was attached to B)  x_1 would increase.
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EricPiphany
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Both strings support the same weight so they both extend as if the other wasn't there. Imagine a vey large elastic of the same material as a smaller one, the larger one would stretch more under the same force.
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EricPiphany
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However if the two string were in parallel and not in series, the would be sharing the weight, and would not stretch as much. Think of a thicker elastic.
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EricPiphany
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T_1=mg, T_2=mg this is a consequence of the fact that in this model the strings have no mass.
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Louisb19
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(Original post by EricPiphany)
However if the two string were in parallel and not in series, the would be sharing the weight, and would not stretch as much. Think of a thicker elastic.
Well that makes a lot of sense. I didn't know that in series elastic materials worked like this. Does this idea extend to anything else I need to know?
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