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chemistry question

I don't understand how to do it, I tried doing 1dm3 * 1 mol dm-3 to find the moles, then got confused, don't know if its the right first step..(Q1) 10 g of magnesium is added to 1 dm3 of 1 mol dm-3copper(II) sulfate solution andthe mixture is stirred until no further reaction occurs..Which of the following is a result of this reaction?
A The resulting solution is colourless.
B 10 g of copper is displaced
C 63.5 g of copper is displaced.
D All the magnesium reacts.

(edited 8 years ago)

Reply 1

Pigster

How many mol of Mg are added?
How many mol of Cu2+ are present?

Reply 2

qatarownz

Original post by Pigster

How many mol of Mg are added?How many mol of Cu2+ are present?

1? cuz 1:1 ratio?

Reply 3

Pigster

How many mol of Mg were actually added? i.e. how many mol is 10 g of Mg?

Reply 4

mice8cheese

Mass = Mr * moles
moles = mass / Mr
(10)g of magnesium / Mr (24.3)
moles of magnesium = 0.427350427

Molarity = moles / volume
molarity * volume = moles
(1)moldm3 * (1) dm3
moles of CuSO4 = 1

resulting mixture is 0.43 moles of MgSO4 and 0.57 moles of CuSO4
I think thats how it works, but then I am sort of failing chemistry, so I could be wrong.