hey i would really appreaciate if someone could help me, what is the reason for leaving water out in the acid dissociation constant. In my books it says, that water is in excess, so if it is excess, why doesnt it alter the equilibvrium position to the right, according to le chatliers priciple.
So when ethanoic acid is in water, only 0.1 % disscoiates, but isnt the large concetration of water likey to push the quilibrium to the other side?
HELP PLEASE IM STUCK!!!
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Acid dissociation constants watch
- Thread Starter
- 19-06-2004 05:36
- 19-06-2004 08:51
Could Kw have anything to do with it?
Kw=[H+][OH-], where [H+] = [OH-]?
- 19-06-2004 10:05
water is a liquid, and hence cannot be used in Ka expressions as only (aq) and (g) apply in Ka expressions, as liquids are fully concentrated.
is this why?
- 19-06-2004 10:35
wot it is is the water is in such a large excess that even when u alter its volume or concentration a lot it makes no impact on the Ka sum. e.g the amount u alter it makes no change to the overall value of the water!!
hope this makes sense, im not too good at explaining wot i mean!!