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# P2 modulus graphs watch

1. (Original post by Silly Sally)
Everyone is saying "ignore me" - who do i not ignore then???
dont ignore me.

the solution is simple.
2. (Original post by kikzen)
dont ignore me.

the solution is simple.
too late!!! The exam is on Mon and i can't get used to a caluculator in that time!!!
3. Well thanks everyone!!!

I think i understand now - i just have to hope for a nice graphy question
4. (Original post by Silly Sally)
too late!!! The exam is on Mon and i can't get used to a caluculator in that time!!!
Next time, draw a table of points so you can plot graph. You cant go wrong that way. Thats what i'll be doing from now on.
5. (Original post by Silly Sally)
Well thanks everyone!!!

I think i understand now - i just have to hope for a nice graphy question
These equations should be split up into two parts, x>0 and x<0. x>0 is easy its just y = x(x-5), but the problem arises when x<0. Here |x| = -x because |x| = sqrt(x^2) which is always greater then 0, but x is less than 0. So the thing to do when x<0 is to replace |x| with -x but leave x as x so the equation becomes y = -x(x-5).
6. (Original post by It'sPhil...)
These equations should be split up into two parts, x>0 and x<0. x>0 is easy its just y = x(x-5), but the problem arises when x<0. Here |x| = -x because |x| = sqrt(x^2) which is always greater then 0, but x is less than 0. So the thing to do when x<0 is to replace |x| with -x but leave x as x so the equation becomes y = -x(x-5).
Hmmm. Sounds familiar

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