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# p2 question watch

1. can anyone help me on this question pliz?
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2. p2 question.doc (42.5 KB, 94 views)
3. (Original post by Jubba)
can anyone help me on this question pliz?
Ok well if u look carefully, u can c that the bottom in 30cm long..now..

This 30cm=27cosx+BQ

Angles on a straight line =180
So x+90 (a rectangle)+QBA=180
So QBA=90-x
Therefore, BQ=18cos(90-x)

Now cos(90-x)=sin(x)

So BQ=18sinx

Substituting into original gives

30=27cosx+18sinx

divide all by 3 to give

10=9cosx+6sinx

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