differentiating y=e^x^2
dy/dx = 2x * e^x^2
pls can someone explain this?
my thought was e^x^2 = e^2x so dy/dx would be 2e^2x = 2e^x^2
pls can someone explain this?
my thought was e^x^2 = e^2x so dy/dx would be 2e^2x = 2e^x^2
Product rule mate
And e^x^2 =/= e^2x youre saying there that e^(x*x) = e^(x+x) which is false
Take 2x as u, take e^x^2 as v
Then dy/dx = (2x)(2xe^x^2) + 2(e^x^2)
(i think)
edit: I just realised 2x*e^x^2 is the answer not the question
Posted from TSR Mobile
And e^x^2 =/= e^2x youre saying there that e^(x*x) = e^(x+x) which is false
Take 2x as u, take e^x^2 as v
Then dy/dx = (2x)(2xe^x^2) + 2(e^x^2)
(i think)
edit: I just realised 2x*e^x^2 is the answer not the question
Posted from TSR Mobile
(edited 8 years ago)
answer: (2x)(e^x^2)
let u = x^2 du/dx = 2x
when y = e^u dy/du = e^u
therefore dy/dx = (e^u)(du/dx) = (e^u)(2x) = (2x)(e^x^2)
let u = x^2 du/dx = 2x
when y = e^u dy/du = e^u
therefore dy/dx = (e^u)(du/dx) = (e^u)(2x) = (2x)(e^x^2)
(edited 8 years ago)
chain rule:
y = e^u
u = x^2
du/dx = 2x
dy/du = e^u (derivative of e^u is e^u)
dy/dx = du/dx * dy/du = 2x * e^u = 2xe^(x^2)
y = e^u
u = x^2
du/dx = 2x
dy/du = e^u (derivative of e^u is e^u)
dy/dx = du/dx * dy/du = 2x * e^u = 2xe^(x^2)
Original post by eternaforest
Product rule mate
And e^x^2 =/= e^2x youre saying there that e^(x*x) = e^(x+x) which is false
Take 2x as u, take e^x^2 as v
Then dy/dx = (2x)(2xe^x^2) + 2(e^x^2)
(i think)
Posted from TSR Mobile
And e^x^2 =/= e^2x youre saying there that e^(x*x) = e^(x+x) which is false
Take 2x as u, take e^x^2 as v
Then dy/dx = (2x)(2xe^x^2) + 2(e^x^2)
(i think)
Posted from TSR Mobile
I'm really not sure why you think the product rule is appropriate here. You want the chain rule mate.
Original post by studentro
I'm really not sure why you think the product rule is appropriate here. You want the chain rule mate.
2x*e^x^2 they r two different functions so product rule is needed?
Edit: nvm I realised that's the answer not the question
Posted from TSR Mobile
(edited 8 years ago)
Stupid question but
indicies?
indicies?
Original post by GeologyMaths
Stupid question but
indicies?
indicies?
Prettyvsure u made same mistake as op, you're implying x+x = x*x
Posted from TSR Mobile
Original post by GeologyMaths
Stupid question but
indicies?
indicies?
x*x = x^2
x+x = 2x
x^2 does not equal 2x
Original post by eternaforest
Ah, you've misread the question. They asked for help differentiating y=e^x^2 - they asked asked why dy/dx = 2x*e^x^2.
Edit: nvm, noticed you already spotted this
Original post by GeologyMaths
Stupid question but
indicies?
indicies?
(edited 8 years ago)
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