P2 HelpWatch

This discussion is closed.
#1
Could anyone please provide an answer for the following. No explanation required, just need to check I've done it right! Thanks in advance.

2x^3 +5x +13 divided by x^2 +3x -1
14 years ago
#2
(Original post by savvy10)
Could anyone please provide an answer for the following. No explanation required, just need to check I've done it right! Thanks in advance.

x^2 +3x -1 / 2x^3 +5x +13
Whats the question!?
0
#3
Sorry, wrong way round...

2x^3 +5x +13 divided by x^2 +3x -1
14 years ago
#4
(Original post by savvy10)
Sorry, wrong way round...

2x^3 +5x +13 divided by x^2 +3x -1
But still, what do you want us to do? What is the question!?
0
#5

Divide 2x^3 +5x +13 by x^2 +3x -1
14 years ago
#6
(Original post by savvy10)

Divide 2x^3 +5x +13 by x^2 +3x -1
u cant nicely
0
#7
Well, you can because I did it in my mock, only I've forgotton exactly how I did it!
14 years ago
#8
maybe u have got sum + sign where u should have a - sign?
0
#9
Nope, I've got the question here in front of me.
14 years ago
#10
wot paper/q from text book??/
0
#11
Well, I've only got the photocopy on a worksheet, but I think our mock was OCR P2 June 2003.
14 years ago
#12
(Original post by savvy10)

Divide 2x^3 +5x +13 by x^2 +3x -1
polynomial division::

= (2x - 6) + (21x-7)/(x^2 + 3x -1) i think

but this is harder than most of the algebraic division in P4...
0
#13
Yeh OCR are often *******s and set stuff like this. Cheers for that, I've given you some +ve rep KerChing.
14 years ago
#14
(Original post by KerChing)
polynomial division::

= (2x - 6) + (21x-7)/(x^2 + 3x -1) i think

but this is harder than most of the algebraic division in P4...
is that seriously the answer u were looking for????
0
#15
Oops! Sorry I didn't see the / sign still. No, sorry it will be in the form of a single polynomial. This isn't rational functions in P4, just division of polynomials. I haven't yet found my answer, so anymore suggestions would be a great help!
14 years ago
#16
(Original post by savvy10)
Oops! Sorry I didn't see the / sign still. No, sorry it will be in the form of a single polynomial. This isn't rational functions in P4, just division of polynomials. I haven't yet found my answer, so anymore suggestions would be a great help!
well it doesnt work
0
14 years ago
#17
damn it i dunno if i did it wrong but ive got a remiander of 25x + 19 or 25x -7 or something cant remember
0
#18
As I've said before, it does work. Thanks Wolf, it should have a remainder so that should be ok.
14 years ago
#19
(Original post by savvy10)
As I've said before, it does work. Thanks Wolf, it should have a remainder so that should be ok.
yea ther is a remainder - if you do a long division - remember to put it 2x^3 + 0x^2 + 5x +13
0
14 years ago
#20
(Original post by TheWolf)
damn it i dunno if i did it wrong but ive got a remiander of 25x + 19 or 25x -7 or something cant remember
i got 25x+7 (u should do 13-6 not 13+6)
0
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