# p2 - what are end points?Watch

This discussion is closed.
#1
what are end points of a curve?
0
14 years ago
#2
(Original post by TheWolf)
what are end points of a curve?
wtf? question example possible??
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#3
example:

sketch

(a) y = arcsin x -1<x<1

stating the coordinates of the end points of your curves in each case
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14 years ago
#4
(Original post by TheWolf)
example:

sketch

(a) y = arcsin x -1<x<1

stating the coordinates of the end points of your curves in each case
surely the end points would be at the end of the range of x i.e. (1,90) and (-1,270)

but i suppose that doesnt make sense as after all (1,36000090) would be a point on the curve
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14 years ago
#5
Well the end points would be when x=-1 and x=1, because that is the domain of the function given. So the end points are:

(-1, arcsin -1) to (1, arcsin 1)
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#6
no idea - is it the maximum/minimum or the assymptotes?
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14 years ago
#7
(Original post by mik1a)
Well the end points would be when x=-1 and x=1, because that is the domain of the function given. So the end points are:

(-1, arcsin -1) to (1, arcsin 1)
and wot would be the value for arcsin1??? 90?? or 36000000000000090
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14 years ago
#8
(Original post by lgs98jonee)
and wot would be the value for arcsin1??? 90?? or 36000000000000090
Good point there.
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#9
ahh i know what the end point is now

you just find y at x = -pi/3 and x = pi/3 which are the domains
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14 years ago
#10
(Original post by TheWolf)
ahh i know what the end point is now

you just find y at x = -pi/3 and x = pi/3 which are the domains
yeh but sin of those =sqrt3/2 u sure that is right?
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14 years ago
#11
The domain you gave was -1 < x < 1, and arcsin x within any range can have unlimited values.. eg arcsin 0.5 = 30, 150, 390 etc.
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#12
look, for an arcsin graph, at x=1, y = pi/2, and when x = -1, y= -pi/2, i think these are the end points, so not sure what the stuff above is about
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14 years ago
#13
(Original post by TheWolf)
look, for an arc sin graph, at x=1, y = pi/2, and when x = -1, y= -pi/2, i think these are the end points
ah but arcsin1also equals 10000pi/2...go on try it..there are an infinite number of answers
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#14
0
14 years ago
#15
(Original post by TheWolf)
that is not the whole of the curve only part of it...go on try sin (pi/2+1000000000pi) and see wot u get
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#16
(Original post by lgs98jonee)
that is not the whole of the curve only part of it...go on try sin (1000000pi/2) and see wot u get
i dont need a whole curve -i need the curve within the domain given in the exam question
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14 years ago
#17
(Original post by TheWolf)
i dont need a whole curve -i need the curve within the domain given in the exam question
YEAH i know and sin(pi/2+1000000pi)=1 which is within the domain ffs
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#18
(Original post by lgs98jonee)
YEAH i know and sin(pi/2+1000000pi)=1 which is within the domain ffs
ok show that on the graph?
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14 years ago
#19
(Original post by TheWolf)
ok show that on the graph?
yikes i have just told u...u only have part of the graph

the curve also extends upwards and downwards to infinity
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14 years ago
#20
This is the graph in the domain -1<x<1,
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