How do I know which element marked on this graph is a halogen?

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Adorable98
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The answer is B), but how was I supposed to know that?
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username986184
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(Original post by Adorable98)
The answer is B), but how was I supposed to know that?
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Have you not studied what happens to first IE as you go from left to right across a period?
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rxns_00
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(Original post by Adorable98)
The answer is B), but how was I supposed to know that?
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Going from left to right the proton number increases, so therefore the charge of the nucleus increases while shielding stays relatively the same

What do you think happens to the electrostatic force between the nucleus and outer electors as the charge increases? And so what happens to IE? And so when does IE in a period is at its peak?

It's self explanatory from there
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Adorable98
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(Original post by TeachChemistry)
Have you not studied what happens to first IE as you go from left to right across a period?
Yes, I have.
I'm aware that there must be 2 drops in the graph, one between groups 2 and 3 and the other between group 5 and 6.

But, a halogen is in group 7, so if B is a halogen how come there's a drop after group 7 according to this graph?!
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username986184
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(Original post by Adorable98)
Yes, I have.
I'm aware that there must be 2 drops in the graph, one between groups 2 and 3 and the other between group 5 and 6.

But, a halogen is in group 7, so if B is a halogen how come there's a drop after group 7 according to this graph?!
After B the IE goes up as the next element would be a noble gas. THEN there is a large drop as a new period starts.
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Adorable98
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(Original post by RonnieRJ)
Going from left to right the proton number increases, so therefore the charge of the nucleus increases while shielding stays relatively the same

What do you think happens to the electrostatic force between the nucleus and outer electors as the charge increases? And so what happens to IE? And so when does IE in a period is at its peak?

It's self explanatory from there
Yeaah, i know that as you go across the period, atomic radius decreases and the nuclear charge also increases, so more protons, so a greater attraction.

But, a halogen is in group 7, so if B is a halogen how come there's a drop after group 7 according to this graph?!
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Another
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(Original post by Adorable98)
Yeaah, i know that as you go across the period, atomic radius decreases and the nuclear charge also increases, so more protons, so a greater attraction.

But, a halogen is in group 7, so if B is a halogen how come there's a drop after group 7 according to this graph?!
The peak in the graph is group 8. The drop happens at Group 1 of the next line, after group 8
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rxns_00
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(Original post by Adorable98)
Yeaah, i know that as you go across the period, atomic radius decreases and the nuclear charge also increases, so more protons, so a greater attraction.

But, a halogen is in group 7, so if B is a halogen how come there's a drop after group 7 according to this graph?!
B isn't at the peak though. B is the element just before the peak.

The peak is at a noble gas, group 0, then there's a drop look closely at the graph. You'll see the cross at the peak, that's the mark for the group 0
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Adorable98
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(Original post by RonnieRJ)
B isn't at the peak though. B is the element just before the peak.

The peak is at a noble gas, group 0, then there's a drop look closely at the graph. You'll see the cross at the peak, that's the mark for the group 0
(Original post by Another)
The peak in the graph is group 8. The drop happens at Group 1 of the next line, after group 8
(Original post by TeachChemistry)
After B the IE goes up as the next element would be a noble gas. THEN there is a large drop as a new period starts.
I honestly just realised that I could've just counted the dots on the line graph!! :facepalm:

Anyway, thanks all of you!!!
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charco
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(Original post by Adorable98)
I honestly just realised that I could've just counted the dots on the line graph!! :facepalm:

Anyway, thanks all of you!!!
Not necessarily as the graph may be given from any element at the start.
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Adorable98
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(Original post by charco)
Not necessarily as the graph may be given from any element at the start.
Really?!:zomg:
So the only thing I should do is look at the no. of drops?!
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charco
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(Original post by Adorable98)
Really?!:zomg:
So the only thing I should do is look at the no. of drops?!
Look for the big and small inflexions
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Adorable98
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(Original post by charco)
Look for the big and small inflexions
I see.. thanks once again!!
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