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#1
Report Thread starter 15 years ago
#1
f(x) = 0 for x<0
= 1/8(x^2 +ax) for 0<=x<=2
= 1 for x > 0

find value of a so that it is a valid cdf.
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lgs98jonee
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#2
Report 15 years ago
#2
(Original post by Jubba)
F(x) = 0 for x<0
= 1/8(x^2 +ax) for 0<=x<=2
= 1 for x > 2

find value of a so that it is a valid cdf.
assuming it should be a 2 and not a 0 and also that it is a F and not a f

when x=2, F(x)=1
so (x^2+ax)/8=1
so x^2+ax=8
so 4+2a=8
so a=2
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Olden
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#3
Report Thread starter 15 years ago
#3
oh yes i c my mistakes! thanks a lot!
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