# s2 help

Watch
This discussion is closed.
#1
f(x) = 0 for x<0
= 1/8(x^2 +ax) for 0<=x<=2
= 1 for x > 0

find value of a so that it is a valid cdf.
0
15 years ago
#2
(Original post by Jubba)
F(x) = 0 for x<0
= 1/8(x^2 +ax) for 0<=x<=2
= 1 for x > 2

find value of a so that it is a valid cdf.
assuming it should be a 2 and not a 0 and also that it is a F and not a f

when x=2, F(x)=1
so (x^2+ax)/8=1
so x^2+ax=8
so 4+2a=8
so a=2
0
#3
oh yes i c my mistakes! thanks a lot!
0
X
new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### If you do not get the A-level grades you want this summer, what is your likely next step?

Take autumn exams (21)
39.62%
Take exams next summer (12)
22.64%
Change uni choice through clearing (14)
26.42%
Apply to uni next year instead (5)
9.43%
I'm not applying to university (1)
1.89%