# PHYA4 simple harmonic motion questionWatch

Thread starter 3 years ago
#1
http://filestore.aqa.org.uk/subjects...2-QP-JUN13.PDF

Question 1) b) ii)

You're asked to calculate the acceleration.

They appear to use the formula a = (2 x pi x f)^2 x A

but isn't this formula supposed to be the maximum acceleration? how do you know that it is the maximum?
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3 years ago
#2
Maximum acceleration is when the pendulum is stationary (at maximum displacement). That means that the amplitude is 42 x 2 = 84mm.
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3 years ago
#3
a=-(2πf)2x

x is the displacement from the equilibrium point

for a given pendulum in SHM the acceleration is always the same at displacement x whatever the amplitude of the oscillation... because the condition for SHM is a restoring force proportional to displacement (but opposite in direction)
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