Chemistry equation please help
So I'm following the reaction between potassium manganate (VII) and Ethanedioc acid. Which can be stopped by adding potassium iodide, which forms iodine and stops the manganate ions from reacting further.
I will then titrate this solution with sodium thiosulphate
Im trying to get at a reaction for all of this so far I have
5H2C2O4 (aq) + 2KMnO4 (aq) +3H2SO4 (aq) → 2MnSO4 (aq) + K2SO4 (aq) + 10CO2 (g) + 8H2O (l)
MnO4- (aq) + 5I- (aq) + 8H+ (aq) → Mn2+ (aq) + 21/2 I2 (aq) + 4H2O (l)
I2 (aq) + 2S2O32- (aq) → 2I- (aq) + S4O62- (aq)
I will then titrate this solution with sodium thiosulphate
Im trying to get at a reaction for all of this so far I have
5H2C2O4 (aq) + 2KMnO4 (aq) +3H2SO4 (aq) → 2MnSO4 (aq) + K2SO4 (aq) + 10CO2 (g) + 8H2O (l)
MnO4- (aq) + 5I- (aq) + 8H+ (aq) → Mn2+ (aq) + 21/2 I2 (aq) + 4H2O (l)
I2 (aq) + 2S2O32- (aq) → 2I- (aq) + S4O62- (aq)
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Original post by Akhaten
So I'm following the reaction between potassium manganate (VII) and Ethanedioc acid. Which can be stopped by adding potassium iodide, which forms iodine and stops the manganate ions from reacting further.
I will then titrate this solution with sodium thiosulphate
Im trying to get at a reaction for all of this so far I have
5H2C2O4 (aq) + 2KMnO4 (aq) +3H2SO4 (aq) → 2MnSO4 (aq) + K2SO4 (aq) + 10CO2 (g) + 8H2O (l)
MnO4- (aq) + 5I- (aq) + 8H+ (aq) → Mn2+ (aq) + 21/2 I2 (aq) + 4H2O (l)
I2 (aq) + 2S2O32- (aq) → 2I- (aq) + S4O62- (aq)
I will then titrate this solution with sodium thiosulphate
Im trying to get at a reaction for all of this so far I have
5H2C2O4 (aq) + 2KMnO4 (aq) +3H2SO4 (aq) → 2MnSO4 (aq) + K2SO4 (aq) + 10CO2 (g) + 8H2O (l)
MnO4- (aq) + 5I- (aq) + 8H+ (aq) → Mn2+ (aq) + 21/2 I2 (aq) + 4H2O (l)
I2 (aq) + 2S2O32- (aq) → 2I- (aq) + S4O62- (aq)
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