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# How do I find the Inverse of This Function? [P2] watch

1. f:x |----> (x+3)^2 +1
2. (Original post by Sang)
f:x |----> (x+3)^2 +1
x = (y+3)^2 + 1.

So y = (x-1)^1/2 - 3
3. (Original post by Sang)
f:x |----> (x+3)^2 +1
it doesnt actually have an inverse unless the doomain of x>=-3 is stated
4. In general just express x in terms of y, then swap the symbols (or the other way around, swap the symbols then get back to expressing y in terms of x, which ever you prefer).

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Updated: June 20, 2004
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