Please can someone clarify, does lattice dissociation enthalpy = lattice formation enthalpy?
As in ΔHf - ΔHat of metal - ΔHat of non-metal - ΔHi of metal - ΔHea of non-metal = ΔH of lattice formation/dissociation
If that makes sense (in terms of Born-Haber cycle). Thanks (I'm taking my Chemistry with the AQA exam board if that helps)?
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Lattice Enthalpy watch
- Thread Starter
- 15-01-2016 17:48
- 15-01-2016 18:05
Formation is the opposite of dissociation. They'll have the same value, just opposite signs, i.e. formation is -ve.