Hey there! Sign in to join this conversationNew here? Join for free

Edexcel IAL Maths - Mechanics 1 - WME01 25 Jan 2016 Watch

Announcements
    Offline

    21
    ReputationRep:
    (Original post by omar5478)
    Honestly, I would say that it is a really annoying paper, but maybe thats just because I am pretty bad at practical stuff.Good luck anyways.
    I agree wholeheartedly and share your sentiments. I'm not expecting a good grade tomorrow.
    Offline

    5
    ReputationRep:
    (Original post by Zacken)
    I agree wholeheartedly and share your sentiments. I'm not expecting a good grade tomorrow.
    I guess we will have to hope that other candidates score low so that the boundaries are get for us lol.
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by Zacken)
    I agree wholeheartedly and share your sentiments. I'm not expecting a good grade tomorrow.
    me neither
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by omar5478)
    I guess we will have to hope that other candidates score low so that the boundaries are get for us lol.
    i was saying the exact same thing to my friends
    Offline

    0
    ReputationRep:
    Guys i also made simple mistakes! i couldn't get the range of the moment and by chance my value for Q.2 came 73/10u due west! i dont know why this value is wrong, as i did the question with utter care! just bad luck it is
    Offline

    21
    ReputationRep:
    (Original post by syed.shahriyar)
    Guys i also made simple mistakes! i couldn't get the range of the moment and by chance my value for Q.2 came 73/10u due west! i dont know why this value is wrong, as i did the question with utter care! just bad luck it is
    A lot of people seem to be getting this answer, but I think I suspect where you went wrong. It seems to be a fairly common "trap" in the question - but I might also just be wrong myself.
    Offline

    5
    ReputationRep:
    (Original post by syed.shahriyar)
    Guys i also made simple mistakes! i couldn't get the range of the moment and by chance my value for Q.2 came 73/10u due west! i dont know why this value is wrong, as i did the question with utter care! just bad luck it is
    Can you please describe how you got this answer because I am really curious to how the direction could be due west.Moreover,what was your value for Q2)a ??
    Offline

    0
    ReputationRep:
    (Original post by omar5478)
    Can you please describe how you got this answer because I am really curious to how the direction could be due west.Moreover,what was your value for Q2)a ??
    I=33/5 mu, m=2m, u=4u

    => I=mv-mu
    => 33/5mu=2mv-(2 x 4u)
    => 33/5mu=2mv-8mu
    => 33/5mu + 8mu = 2mv
    => 73/5u = 2v
    => 73/10u = v
    v = 73/10u

    This is what i did! i hope i did correctly or is it wrong then plz correct! :/ confused
    Offline

    21
    ReputationRep:
    (Original post by syed.shahriyar)
    I=33/5 mu, m=2m, u=4u

    => I=mv-mu
    => 33/5mu=2mv-(2 x 4u)
    => 33/5mu=2mv-8mu
    => 33/5mu + 8mu = 2mv
    => 73/5u = 2v
    => 73/10u = v
    v = 73/10u

    This is what i did! i hope i did correctly or is it wrong then plz correct! :/ confused
    Thing is, the magnitude of the impulse is 33/5 mu, you need to work out the direction yourself.
    Offline

    5
    ReputationRep:
    (Original post by syed.shahriyar)
    I=33/5 mu, m=2m, u=4u

    => I=mv-mu
    => 33/5mu=2mv-(2 x 4u)
    => 33/5mu=2mv-8mu
    => 33/5mu + 8mu = 2mv
    => 73/5u = 2v
    => 73/10u = v
    v = 73/10u

    This is what i did! i hope i did correctly or is it wrong then plz correct! :/ confused
    According to your working, the final velocity is positive(thus same direction as original) and bigger than the original velocity.This can only happen if the object was pushed which clearly was not the case. Your mistake here was that you assumed that the impulse was positive,while the negative value of impulse's magnitude should have been used.If were you, I won't be worried because a lot of people seem to have made this mistake which will lower the grade boundaries.
    Offline

    5
    ReputationRep:
    (Original post by Zacken)
    Thing is, the magnitude of the impulse is 33/5 mu, you need to work out the direction yourself.
    Exactly.
    Offline

    0
    ReputationRep:
    Well happy about the overall exam!
    Offline

    0
    ReputationRep:
    hey guys for the speed time graph of the rock projection , is the graph a straight line starting from a speed of 11 to a -14 ??
    Offline

    21
    ReputationRep:
    (Original post by Mohammad_besani)
    hey guys for the speed time graph of the rock projection , is the graph a straight line starting from a speed of 11 to a -14 ??
    A straight line start from 11.2 to -14 and cross the time-axis at (14/g, 0) or (1.43, 0).
    Offline

    14
    ReputationRep:
    (Original post by Zacken)
    Before telling you how many marks you are going to lose, I'm afraid one of us have read the question wrong. I was fairly sure the question had said the mass of the block is 8 kg and not 5 kg. I can only ask the others to confirm:

    Spoiler:
    Show
    PlayerBB Sumaiyya1999
    What was the mass of the block in Q3?

    By the way, Omar - what did you get for Q2?
    Hey, sorry I just saw it and the mass is not 5 kg because I remember how I did it and I got a different answer, and I am sure I did it right because I revised the numberes so I think @Zacken is the right one

    Posted from TSR Mobile
    Offline

    14
    ReputationRep:
    (Original post by Zacken)
    Fewer questions than usual, so more marks per question, more structure than usual. There wasn't the easy speed-time things with distance between two places, etc... but the paper was fairly standard, no thinking required. There'll be high boundaries.

    1. (a) F = 2,200 N
    (b) M = 800.
    (c) Same acceleration for system/trailer as truck.

    2. (a) 7u/10 due east
    (b) 6u/5 due east.

    3. \displaystyle T = \frac{16g}{5\sqrt{3} + 1}

    4. (a) h_max = 10
    (b) \displaystyle t_{\text{total}} = \frac{28}{g} \approx 2.86

    5. (a) (i) T_A = 94 - 10x
    (ii) T_B = 66 + 10x
    (b) 1 \leq x \leq 1.8

    6. (a) \sqrt{68} = 2\sqrt{17} \approx 8.25
    (b) (5+2t)i + (5t-3)j
    (c) (7-3t)i + (5-15t)j
    (d) t = 2/5 so time 2:24 PM
    (e) 29/5i - j

    7 (a) T - g/2 = 2a
    (b) 3g - T = 5a
    (c) (i) a = 5g/14
    (ii) T = 17g/14
    (d) d= 17/14 (by letting g=1 in c(ii)).
    Hey I got the same answers as you!

    Posted from TSR Mobile
    Offline

    21
    ReputationRep:
    (Original post by PlayerBB)
    Hey I got the same answers as you!

    Posted from TSR Mobile
    Everything exactly the same? If so, congratulations!
    Offline

    14
    ReputationRep:
    (Original post by Zacken)
    A straight line start from 11.2 to -14 and cross the time-axis at (14/g, 0) or (1.43, 0).
    I started the line from 7.sth because I thought they asked from the instant when it passes A

    Posted from TSR Mobile
    Offline

    14
    ReputationRep:
    (Original post by Zacken)
    Everything exactly the same? If so, congratulations!
    Yeah supposedly haha and thank you mate!! ^.^

    Posted from TSR Mobile
    Offline

    21
    ReputationRep:
    (Original post by PlayerBB)
    I started the line from 7.sth because I thought they asked from the instant when it passes A

    Posted from TSR Mobile
    The question said that at A, the vertical velocity upwards was 11.2
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    How are your GCSEs going so far?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.