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    Hi I'm stuck on this question and I don't understand why I am not getting the answer on the mark scheme please help.

    Question: A is the point (-2,6), and B is the point (3,-8). The line L is perpendicular to the line x-3y+15=0 and passes through the midpoint of AB. Find the equation of L, giving your answer in the form ax+by+c=0, where ABC are integers

    Anyway this is my answer : -3x - y + 1/2 = 0

    The mark scheme says the answer is .6x + 2y - 1 = 0

    Upon typing this question I realised it said INTEGARS so if I multiply my answer by 2 I get
    -6x -2y + 1 = 0

    Is that right or is it still wrong please help me, Thank YOU
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    Yeah that's right. Because if you divide your answer by minus 1 then you get the answer on the mark scheme

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    (Original post by Clovers)
    Yeah that's right. Because if you divide your answer by minus 1 then you get the answer on the mark scheme

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    Or alternatively if you add everything onto the other side
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    (Original post by Cinna21)
    Hi I'm stuck on this question and I don't understand why I am not getting the answer on the mark scheme please help.

    Question: A is the point (-2,6), and B is the point (3,-8). The line L is perpendicular to the line x-3y+15=0 and passes through the midpoint of AB. Find the equation of L, giving your answer in the form ax+by+c=0, where ABC are integers

    Anyway this is my answer : -3x - y + 1/2 = 0

    The mark scheme says the answer is .6x + 2y - 1 = 0

    Upon typing this question I realised it said INTEGARS so if I multiply my answer by 2 I get
    -6x -2y + 1 = 0

    Is that right or is it still wrong please help me, Thank YOU
    ops didn't read the whole post
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    (Original post by MathsAndCompSci)
    No it's not. Is   \frac {1}{2} a integer fam?
    I know I already realised that read everything I wrote please, Thank You
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    (Original post by jamestg)
    Or alternatively if you add everything onto the other side
    So its definitely right ?? Thanks for your help :P
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    (Original post by Clovers)
    Yeah that's right. Because if you divide your answer by minus 1 then you get the answer on the mark scheme

    Posted from TSR Mobile

    So its right then ? Phewy Thanks
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    When you get to y= -3x + 1/2 , you need to get rid of the fraction first by multiplying the whole equation by 2, before you put the equation into the form ax+by+c=0
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    (Original post by jessyjellytot14)
    When you get to y= -3x + 1/2 , you need to get rid of the fraction first by multiplying the whole equation by 2, before you put the equation into the form ax+by+c=0
    I will remember that thanks
 
 
 
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