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    wot is e^(kx+1) intergrated??
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    1/k e^kx+1

    aint that p3 work?
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    1/k . e^(kx+1) + constant
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    so with e^(.5x+1)between limits of 2 and -2 do u get 12.8 (i.e. 2e^2-2)
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    Probably because he fancies you. What module is this for? It's in my P2, so I'd be disappointed if this was in other people's P3s.
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    (Original post by savvy10)
    Probably because he fancies you. What module is this for? It's in my P2, so I'd be disappointed if this was in other people's P3s.
    What board you got, this doesn't look familiar in my P2 (OCR). We intergrate E^X but not with (Kx+2) etc I think, actually lookin at it, i could do it.
    Perhaps it is in my P2 :confused:
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    (Original post by Wise Man)
    u blatently r gay
    y?
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    (Original post by Sza)
    What board you got, this doesn't look familiar in my P2 (OCR). We intergrate E^X but not with (Kx+2) etc I think, actually lookin at it, i could do it.
    Perhaps it is in my P2 :confused:
    it was in a p2 paper but with using the trapezium rule...just wanted to check my answer
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    Yep, I'm doing OCR P2 as well. We probably don't need to know it, our teaches don't tend to focus on modules when they teach unfortunatly!

    Wiseman, did you just touch my ass?
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    Don't use big words like 'Maths', it might confuse him.
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    look at his quite disturbing last few threads http://www.uk-learning.net/search.php?searchid=275162
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    (Original post by Wise Man)
    ur gay!
    LOL....random
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    I doubt very much whether this kid knows one end of a quadratic from another. He's full of bull.
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    (Original post by lgs98jonee)
    this is an academic forum for people wanting to revise for sum quite tricky maths exams this week
    as igs98jonee said.....lets keep it at that ay?
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    On a similar subject...

    What would be the integral of

    y=(4x+3)^10

    This is on the OCR P2 Jan 02 paper...
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    (Original post by jwoolley)
    On a similar subject...

    What would be the integral of

    y=(4x+3)^10

    This is on the OCR P2 Jan 02 paper...
    i think it should be:

    [(4x+3)^11](1/11)(1/4)
    = [(4x+3)^11] / 44
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    (Original post by mockel)
    i think it should be:

    [(4x+3)^11](1/11)(1/4)
    = [(4x+3)^11] / 44
    u sure that is p2 isnt it p3??? is it not a bin expansion q
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    (Original post by jwoolley)
    On a similar subject...

    What would be the integral of

    y=(4x+3)^10

    This is on the OCR P2 Jan 02 paper...
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    (Original post by mockel)
    i think it should be:

    [(4x+3)^11](1/11)(1/4)
    = [(4x+3)^11] / 44
    Thats what the integrator website thing said too so I think its right. Where does the 1/4 come from though? Is the rule to divide by the derivative of the bracket's contents?
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    (Original post by lgs98jonee)
    u sure that is p2 isnt it p3??? is it not a bin expansion q
    oh yeah, that's what i would do in p3....you're right, they are probably expecting a binomial expansion- but they can't expect you to do the whole thing, can they?
 
 
 
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