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Algeba- multiplying & factorising watch

multiply out the brackets & collect like terms:
1) 8( 4b-2) +8(3b-2)
2) 5r - 8(6r - 9) + 3( 8r - 3)
3) 6(8i -9 ) + 3(8i - 3) - 4i
4) 5a( 5a -2 ) + 8 ( 7a - 1)

multiply out the brackets only:
4) -2q( 8q - 5)

factorise:
1) 9i + 36
2) -9x + 45
3) 12i + 9
4) 4k^2 - 36k
5) -15k + 18k^2
2. I'm actually studying this for my exam tomorrow. For the multiplicaton ones, you multiply each term in the bracket by the number outside the bracket. For examile... 8(4b-2) is 8 lots of (4b-2). So that's 8*4b+8*2. In other words, 32b-16.

For the factorisation, you need to look for common factors in the multipliers. For example, 9i+36: 9 goes into both 9 and 36. So then you take that number outside the bracket and divide all terms by it. That answer would be 9(i+4).

For factorisation with indices (Q4+5) you can place both a number and a letter outside. For Q4, 4k^2-36k would become 4k(k-9)

And for Q5, it's easier if you write it as 18k^2-15k as a-b is the same as (-b)+a.
3. What have you done so far? Care to post your workings?
4. (Original post by LycanDragon)
I'm actually studying this for my exam tomorrow. For the multiplicaton ones, you multiply each term in the bracket by the number outside the bracket. For examile... 8(4b-2) is 8 lots of (4b-2). So that's 8*4b+8*2. In other words, 32b-16.

For the factorisation, you need to look for common factors in the multipliers. For example, 9i+36: 9 goes into both 9 and 36. So then you take that number outside the bracket and divide all terms by it. That answer would be 9(i+4).

For factorisation with indices (Q4+5) you can place both a number and a letter outside. For Q4, 4k^2-36k would become 4k(k-9)

And for Q5, it's easier if you write it as 18k^2-15k as a-b is the same as (-b)+a.
ty!!

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Updated: January 24, 2016
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