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# Integrating trig quick question!? watch

1. For this problem:

I have gone about my working in this way:

=

I think I have done something wrong.... :s
2. if you integrate sec2 you get tan

if you integrate cosec2 you get.....
3. (Original post by the bear)
if you integrate sec2 you get tan

if you integrate cosec2 you get.....
Wait.. why is this to do with sec2 and cosec2's ?
4. (Original post by Funky_Giraffe)
Wait.. why is this to do with sec2 and cosec2's ?
because

is cosec2x
5. It's not exactly clear what you did in your workings but you appear to be missing a minus sign
6. (Original post by Funky_Giraffe)
For this problem:

I have gone about my working in this way:

=

I think I have done something wrong.... :s

Inspecting what you have written, I believe you were attempting to use the proven result of = , where f(x)= sin x and n= -2.

Unfortunately, this is not feasible because f'(x)=cos x is not present in the original integral. For some unknown reason you made this term surface all of a sudden, which makes no sense.

Like the rest have mentioned, there is a simple result for integrating cosec^2 x wrt x.

Hope this helps. Peace.

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Updated: January 18, 2016
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