# Help with questions C1 Surds

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Can someone show some step by step solutions to these two questions

Thank You in advance.

Thank You in advance.

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#2

Full solutions are not to be shared on this forum.

I will get you started on Q7.

3^(2x+1) * 9^x = 27

3^(2x+1) * (3^2)^x = 27

3^(2x+1) * (3^2x)= 27

Can you use the law a^b * a^c = a^ (b+c) now?

Can you therefore solve for x subsequently using simple logarithms?

Peace.

I will get you started on Q7.

3^(2x+1) * 9^x = 27

3^(2x+1) * (3^2)^x = 27

3^(2x+1) * (3^2x)= 27

Can you use the law a^b * a^c = a^ (b+c) now?

Can you therefore solve for x subsequently using simple logarithms?

Peace.

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#4

(Original post by

Full solutions are not to be shared on this forum.

I will get you started on Q7.

3^(2x+1) * 9^x = 27

3^(2x+1) * (3^2)^x = 27

3^(2x+1) * (3^2x)= 27

Can you use the law a^b * a^c = a^ (b+c) now?

Can you therefore solve for x subsequently using simple logarithms?

Peace.

**WhiteGroupMaths**)Full solutions are not to be shared on this forum.

I will get you started on Q7.

3^(2x+1) * 9^x = 27

3^(2x+1) * (3^2)^x = 27

3^(2x+1) * (3^2x)= 27

Can you use the law a^b * a^c = a^ (b+c) now?

Can you therefore solve for x subsequently using simple logarithms?

Peace.

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#5

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#7

(Original post by

Maybe it depends on the exam board. But you don't learn logs until c2.

**Kholmes1**)Maybe it depends on the exam board. But you don't learn logs until c2.

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#8

Lol I just want to solutions. The answer to both is x=1/2 but I want to know how it got there, stupid books dont give solutions.

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#9

(Original post by

The question is from an edexcel paper. So indices laws should be used not logs. Because for logs a calculator is required

**bobjon22444**)The question is from an edexcel paper. So indices laws should be used not logs. Because for logs a calculator is required

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#10

(Original post by

Maybe it depends on the exam board. But you don't learn logs until c2.

**Kholmes1**)Maybe it depends on the exam board. But you don't learn logs until c2.

**bobjon22444**)

The question is from an edexcel paper. So indices laws should be used not logs. Because for logs a calculator is required

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#11

**WhiteGroupMaths**)

Full solutions are not to be shared on this forum.

I will get you started on Q7.

3^(2x+1) * 9^x = 27

3^(2x+1) * (3^2)^x = 27

3^(2x+1) * (3^2x)= 27

Can you use the law a^b * a^c = a^ (b+c) now?

Can you therefore solve for x subsequently using simple logarithms?

Peace.

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#12

Its from a pearson book called revisons work book. I cant seem to find the solutions either.

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#14

(Original post by

Is the answer for part a, x= 1/2?

**zigocarn**)Is the answer for part a, x= 1/2?

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#16

(Original post by

LOL no its index laws.

**bobjon22444**)LOL no its index laws.

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#17

(Original post by

Yes but how did you get it. It must be without logs.

**bobjon22444**)Yes but how did you get it. It must be without logs.

What you want to do first is make the bases the same for all three values.

Once the bases are the same, you are able to add the powers.

Remember that the power for both sides are equal to each other and this is why you can solve for x.

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#18

(Original post by

Yes but how did you get it. It must be without logs.

**bobjon22444**)Yes but how did you get it. It must be without logs.

Then use the rule to solve for x

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#19

(Original post by

Make everything be in the form of 3 to the power something. For example 27 would be .

Then use the rule to solve for x

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**Andy98**)Make everything be in the form of 3 to the power something. For example 27 would be .

Then use the rule to solve for x

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#20

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