who are the lovely people who want to integrate
please - my p3 exam is tomorrow - eek!!!!
rep if you want it!!
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integrate things for me!! watch
- Thread Starter
- 20-06-2004 16:42
- 20-06-2004 16:44
i wont do them but
use the cos2x = 2cos^2 x - 1 = 1 - 2sin^2 x
(yes i would like rep )
- 20-06-2004 16:47
I will not do the whole method for you but the idea is to use trig identities; we have
cos(2x) = cos^2(x) - sin^2(x)
Which means that
cos(2x) = 1 - 2sin^2(x) and cos(2x) = 2cos^2(x) - 1
sin^2(x) = ( 1-cos(2x) )/2 and cos^2(x) = ( 1+cos(2x) )/2
which you can use to integrate sin^2(x) and cos^2(x). I hope this helps.