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I will not do the whole method for you but the idea is to use trig identities; we have
cos(2x) = cos^2(x) - sin^2(x)
Which means that
cos(2x) = 1 - 2sin^2(x) and cos(2x) = 2cos^2(x) - 1
Rearranging gives
sin^2(x) = ( 1-cos(2x) )/2 and cos^2(x) = ( 1+cos(2x) )/2
which you can use to integrate sin^2(x) and cos^2(x). I hope this helps.
cos(2x) = cos^2(x) - sin^2(x)
Which means that
cos(2x) = 1 - 2sin^2(x) and cos(2x) = 2cos^2(x) - 1
Rearranging gives
sin^2(x) = ( 1-cos(2x) )/2 and cos^2(x) = ( 1+cos(2x) )/2
which you can use to integrate sin^2(x) and cos^2(x). I hope this helps.
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