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Edexcel Core 3 - 21st June 2016 AM Watch

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    (Original post by mathsmo19)

    4) 273.9,33
    Wasn't it 274.9? Or am I remembering it wrong :laugh:
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    (Original post by nishofficial)
    How did you prove it was cotx?
    As far as I remember, in the end you get (1-sin^2x)/sinxcosx = cos^x/sinxcosx = cotx
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    the questions for all the 'easy' topics weren't all that easy this time like even that fraction question was tricky (q7?)


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    there is a sign change, you needed to create a new function f(x) that was g(x) take away the equation of the second line
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    What a shitshow
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    How did every express 2 cos theta - sin theta in the form R cos (theta + a) ?
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    mixed feelings about that one, don't think I will have got the A that I needed
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    What the **** was that?!! Lmao
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    (Original post by nishofficial)
    How did you prove it was cotx?
    Change tan and cots into sin and cos
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    LOVED IT! (except for some dodgy bits in the last question) will arsey be doing model answers this year?
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    (Original post by timelizard)
    goodbye to that A* I had hoped for
    sameeee
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    (Original post by Dark knight123)
    They never have done 3 marks difference between grade C and B always been six or seven.
    You're right, corrected now.
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    why was there a question about partial fractions lol
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    I didn't even complete some questions worst paper I've ever done for sure!!
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    (Original post by mpwb12345)
    How did every express 2 cos theta - sin theta in the form R cos (theta + a) ?
    R=root5
    Theta = 26.57
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    I can happily kiss goodbye to my uni offer hardest paper I've ever seen didn't do like 20 marks (((


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    (Original post by mpwb12345)
    How did every express 2 cos theta - sin theta in the form R cos (theta + a) ?
    Was root 5 and 26.somethon
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    this is the correct method
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    The last question was almost an exact repeat of one that's been up before, otherwise I wouldn't have been able to do it lol
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    (Original post by nishofficial)
    How did you prove it was cotx?
    I used the cos^2(x)-sin^2(x) identity for cos2x, then used a common denominator of 2sin^2(x)cos(x), it all ended up collapsing in itself to get cosx/sinx
 
 
 
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