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# Trig problem watch

1. hello im in need of help with this question i've been having trouble with for the past hour and a half, ive done it several times and keep getting the same answer! Anyway its this

4cosec^2(x) -cot^2(x)= k show that sec^2(x)=k-1/k-4 where k cant equal 4

so im doing this, cot^2(x) = cosec^2(x)-1 so i can substitute
4cosec^2(x) -cosec^2(x) +1 =k
i know 1/sin^2(x) =cosec^2(x) so i can substitute and move the 1 over
4/sin^2(x) -1/sin^2(x) = k-1
combine them togehter so
(4-1)/sin^2(x) = k-1
rearrange 4-1=(k-1)(sin^2(x))
and here is where i get (4-1)/(k-1)=sin^2(x) then i can do 1 over all which gives me
1/sin^2(x) = k-1/4-1
which is sec^2(x) = k-1/4-1 but its meant to be k-4 on the bottom!!! I DONT UNDERSTAND!!!!!!!!!!!! please someone put me out of my misery
2. WOOOOOOOOOOOOOOOOOOOOOO nevermind i did it thanks if u replied anyway

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Updated: January 24, 2016
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