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    Using integration by parts, ntegral(arcsin(x/2)dx
    Limits root3 and 0


    I keep getting the wrong answer and I'm not sure why

    I used u=arcsin(x/2)
    u'=1/2squareroot(1-1/4x^2)

    v'=1
    v=1


    Can anyone help please?

    Thank you in advance to anyone that helps.
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    (Original post by PaigeS1997)
    Using integration by parts, show that integral(arcsin(x/2)dx=1/8
    Limits root3 and 0


    I keep getting the wrong answer and I'm not sure why

    I used u=arcsin(x/2)
    u'=1/2squareroot(1-1/4x^2)

    v'=1
    v=1


    Can anyone help please?
    Please post a photo of your workings
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    (Original post by TeeEm)
    Please post a photo of your workings
    When I entered the limits the answer was wrong
    Attached Images
  1. File Type: pdfpic.pdf (190.4 KB, 58 views)
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    (Original post by PaigeS1997)
    When I entered the limits the answer was wrong
    it is your very last line, the very last term you integrated
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    (Original post by TeeEm)
    it is your very last line, the very last term you integrated
    Thank you, I see now that I have an extra x on it
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    (Original post by PaigeS1997)
    Thank you very much
    no worries
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    (Original post by TeeEm)
    no worries
    Sorry to be a pain but what do I actually do with that x in order to integrate please?
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    (Original post by PaigeS1997)
    Sorry to be a pain but what do I actually do with that x in order to integrate please?
    For some students this is recognisable

    otherwise use the substitution

    u = 4 - x2

    PS
    the a a far better way of doing this integral.
    Post your correct solution first so I cannot be accused of posting full solutions, and I will then post an alternative
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    (Original post by TeeEm)
    For some students this is recognisable

    otherwise use the substitution

    u = 4 - x2

    PS
    the a a far better way of doing this integral.
    Post your correct solution first so I cannot be accused of posting full solutions, and I will then post an alternative
    Got it thank you
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    (Original post by TeeEm)
    For some students this is recognisable

    otherwise use the substitution

    u = 4 - x2

    PS
    the a a far better way of doing this integral.
    Post your correct solution first so I cannot be accused of posting full solutions, and I will then post an alternative
    Thank you, I got -1+pie/root3
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    (Original post by PaigeS1997)
    Thank you, I got -1+pie/root3
    no worries.
    (I have no idea what the answer is as I have not done it)
 
 
 
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