Hey there! Sign in to join this conversationNew here? Join for free

Edexcel A2 C4 Mathematics June 2016 - Official Thread Watch

Announcements
    Offline

    2
    ReputationRep:
    In C3, will we be questioned on the Factor Formulae ? It's not actually mentioned on the Edexcel C3 specification. Will this also mean that we won't get asked to integrate 2sin3xcos2x in C4 ?
    Offline

    20
    ReputationRep:
    (Original post by Danllo)
    In C3, will we be questioned on the Factor Formulae ? It's not actually mentioned on the Edexcel C3 specification. Will this also mean that we won't get asked to integrate 2sin3xcos2x in C4 ?
    I don't think its on the spec (someone correct me if I'm wrong) and from every single past paper I've done I've not encountered it once.
    Offline

    3
    ReputationRep:
    (Original post by Danllo)
    In C3, will we be questioned on the Factor Formulae ? It's not actually mentioned on the Edexcel C3 specification. Will this also mean that we won't get asked to integrate 2sin3xcos2x in C4 ?
    (Original post by XxKingSniprxX)
    I don't think its on the spec (someone correct me if I'm wrong) and from every single past paper I've done I've not encountered it once.
    It's not on the specification.
    Offline

    10
    ReputationRep:
    https://a086a5a2f39bda93734c56a63fab...%20Edexcel.pdf

    Could somebody show what to do in Q7(b)? Thanks!
    Offline

    2
    ReputationRep:
    (Original post by sabahshahed294)
    https://a086a5a2f39bda93734c56a63fab...%20Edexcel.pdf

    Could somebody show what to do in Q7(b)? Thanks!
    Are you struggling to integrate ?
    Offline

    10
    ReputationRep:
    (Original post by Craig1998)
    Are you struggling to integrate ?
    Idk where to start actually. Could you tell me the steps please?
    Offline

    2
    ReputationRep:
    (Original post by sabahshahed294)
    Idk where to start actually. Could you tell me the steps please?
    Try starting by multiplying through by dt.

    As a note, what they ask in part a will usually guide you later in chunkier questions like this.
    Offline

    2
    ReputationRep:
    Attachment 552592552594Name:  image.png
Views: 92
Size:  243.2 KB Hey guys can someone explain the limits used on the integration to find the area ?
    Attached Images
     
    Offline

    10
    ReputationRep:
    (Original post by Craig1998)
    Try starting by multiplying through by dt.

    As a note, what they ask in part a will usually guide you later in chunkier questions like this.
    Um, okay. Thanks!
    Offline

    2
    ReputationRep:
    (Original post by lfcrules)
    Attachment 552592552594Name:  image.png
Views: 92
Size:  243.2 KB Hey guys can someone explain the limits used on the integration to find the area ?
    Anyone know why? I'm kinda confused as well... 13 1 20 8 42
    Online

    19
    ReputationRep:
    (Original post by Don Pedro K.)
    Anyone know why? I'm kinda confused as well... 13 1 20 8 42
    I seem to remember this question frustrating me a lot when prepping for C4, but looking at it now, just seems you're integrating between the two values of t for which x = 5/2, which is kind of intuitive no? Important to note that in this region the integral is positive and you will be getting the "positive area" so to speak
    Offline

    2
    ReputationRep:
    (Original post by 13 1 20 8 42)
    I seem to remember this question frustrating me a lot when prepping for C4, but looking at it now, just seems you're integrating between the two values of t for which x = 5/2, which is kind of intuitive no? Important to note that in this region the integral is positive and you will be getting the "positive area" so to speak
    Could you maybe draw a diagram to show which bits we're finding? Because I thought that we had to find this area:

    Name:  image.jpg
Views: 101
Size:  146.2 KB
    Online

    19
    ReputationRep:
    (Original post by Don Pedro K.)
    Could you maybe draw a diagram to show which bits we're finding? Because I thought that we had to find this area:

    Name:  image.jpg
Views: 101
Size:  146.2 KB
    That is correct. I think I remember where my confusion lied, it was in justifying that the integrand from integrating y with respect to x between these two t points is actually the area. I think this justification is a bit complicated and the question expects you to just assume that the way they have done it, the simple way of just saying "oh we'll integrate ydx and translate to t", will work. I am pretty sure a question like this will not come up.
    Offline

    2
    ReputationRep:
    (Original post by 13 1 20 8 42)
    That is correct. I think I remember where my confusion lied, it was in justifying that the integrand from integrating y with respect to x between these two t points is actually the area. I think this justification is a bit complicated and the question expects you to just assume that the way they have done it, the simple way of just saying "oh we'll integrate ydx and translate to t", will work. I am pretty sure a question like this will not come up.
    But if that is the area that we need to find, surely that would be between the points x = 2 and x = 2.5 so when you sub that in for x = t + 1/t, you get t = 1 and t = 2 not t = 1/2 and t = 2 :s?
    Online

    19
    ReputationRep:
    (Original post by Don Pedro K.)
    But if that is the area that we need to find, surely that would be between the points x = 2 and x = 2.5 so when you sub that in for x = t + 1/t, you get t = 1 and t = 2 not t = 1/2 and t = 2 :s?
    But as you showed earlier in the question x = 2.5 has two t-solutions
    Offline

    13
    ReputationRep:
    (Original post by Don Pedro K.)
    But if that is the area that we need to find, surely that would be between the points x = 2 and x = 2.5 so when you sub that in for x = t + 1/t, you get t = 1 and t = 2 not t = 1/2 and t = 2 :s?
    integrate between 5/2 and 2 is what I would do, definitely looks like that to me
    Have you got an answer for the question?
    Offline

    2
    ReputationRep:
    (Original post by k.russell)
    integrate between 5/2 and 2 is what I would do, definitely looks like that to me
    Have you got an answer for the question?
    This is what I thaught as well , but then would you get the area above the x axis or below ?
    Offline

    2
    ReputationRep:
    (Original post by sabahshahed294)
    Idk where to start actually. Could you tell me the steps please?
    Turn it into partial fractions before integrating
    Offline

    20
    ReputationRep:
    Just want someone to confirm since I remember something faintly from integration by volume of revolutions.

    If you integrating the volume of revolutions by the x axis you do: pi . integral (y)^2 dy/dx
    BUT if you integrate the volume of revolutions by the y axis you do: pi . integral (x)^2 dy/dx

    Correct? :erm:
    Offline

    20
    ReputationRep:
    Q) Those that are sitting their AS level maths is their exams still under the current spec so when they go into
    A2, would they still have a chance to resit some of their exams next year? I thought the exam board (Edexcel)
    will have its A level Maths curriculum changed in 2017 .*. meaning anybody sitting maths exams from 2017
    would be sitting different spec papers .*. would the current AS level maths students under the spec atm be
    affected next year if they would resit?

    :confused: *flashback* @Michael gove :mob:
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Break up or unrequited love?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.