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Edexcel A2 C4 Mathematics June 2016 - Official Thread

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Original post by riffy123
For the volume question, how was it 544pi? It had to be 576pi as u had to work out the whole cylinder and take it away by the integral surely!


It was 544π because radius is 8. 8.5 was the length
π x 8 x 8 x 8.5 =544π

Not rocket science

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any unofficial mark scheme yet?
Reply 4142
Original post by Woodford_97
Fairly sure E is actually (3, 17/5, 4/5) or (-1, 33/5, 16/5) or otherwise it doesnt fit on the line L2.
E = (1,5,2)+k(-5,4,3) so
1-5k=3 --> k= -2/5
5 + 4 x -2/5 = 17/5
2 + 3 x -2/5 = 4/5

You can do the same for the other value of E to work out if its on the line

answers can't always be exactly right but you get the picture
Grade boundary predictions?
Reply 4144
Original post by Zuzuvela
It was 544π because radius is 8. 8.5 was the length
π x 8 x 8 x 8.5 =544π

Not rocket science

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you could integrate it if you wanted to
Original post by Yua
thats volume for under graph, S would be volume of the rectangular part (becomes a cone) subtracted by the volume under the graph


It becomes a cylinder no?
Can someone explain how you were supposed to do the last vector question (8e)?
Original post by ryanroks1
What did everyone get for the normal question where you had to find X? I remember 22 + pi being on the bottom?

Is that the a,b,c and are integers, find their values question?
I remember one of the bottom values was '1', I think it was the coefficient of pi.
Someone quote me when solutions are out please :smile:
Original post by Zuzuvela
It was 544π because radius is 8. 8.5 was the length
π x 8 x 8 x 8.5 =544π

Not rocket science

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Wasn't the height of cylinder 17/2 +1/2 = 9 so Volume = 576pi
(edited 7 years ago)
Original post by ombtom
I got that :colondollar:


So did I 😊


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E was definitely: (-1, 33/5 , 16/5 ) or (3, 17/5 , 4/5 )
Original post by Smithy1597
How was it not 1024pi/5


I got that too, but I think there was a volume between x=0 and x=1/2 which we didn't account for, this I would expect to lose 2 marks, 1 for accuracy one for method
Original post by Yua
(becomes a cone)


Wait do you mean a cylinder? Cos other than that I completely agree x
Original post by Yua
thats volume for under graph, S would be volume of the rectangular part (becomes a cone) subtracted by the volume under the graph


Rectangles become Cylinders, Triangles become Cones.
Original post by ombtom
I got that :colondollar:


Original post by thehollowcrown
i think this is what i got


Even better, hopefully should be 75/75 in this then maybe a few marks lost in some places because I have a tendency to occasionally be an idiot in exams
Original post by thehollowcrown
i think this is what i got


Yh same
Original post by Sophie Wilczek
So did I 😊


How did you do the last vector question? I used unit vectors :eek:

Poll: http://www.thestudentroom.co.uk/showthread.php?t=4184101&p=66066153#post66066153
Original post by CurrentFlow
Wasn't the height of cylinder 17/2 +1/2 = 9 so Volume = 576pi


No the height would be the X axis values,
The radius is y which is why we square y and intergrate

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If I do okay in c3 and c4 say its like B but I do better in s2 can I get at least an A ?

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