Fairly sure E is actually (3, 17/5, 4/5) or (-1, 33/5, 16/5) or otherwise it doesnt fit on the line L2. E = (1,5,2)+k(-5,4,3) so 1-5k=3 --> k= -2/5 5 + 4 x -2/5 = 17/5 2 + 3 x -2/5 = 4/5
You can do the same for the other value of E to work out if its on the line
answers can't always be exactly right but you get the picture
I got that too, but I think there was a volume between x=0 and x=1/2 which we didn't account for, this I would expect to lose 2 marks, 1 for accuracy one for method
Even better, hopefully should be 75/75 in this then maybe a few marks lost in some places because I have a tendency to occasionally be an idiot in exams