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# Edexcel A2 C4 Mathematics June 2016 - Official Thread watch

1. This standard result is quoted in the formula booklet but would anyone like to have a go at it?

2. (Original post by aymanzayedmannan)
This standard result is quoted in the formula booklet but would anyone like to have a go at it?

Spoiler:
Show

3. (Original post by Kvothe the arcane)
Spoiler:
Show

4. (Original post by aymanzayedmannan)
Done .

The intended approach is so unintuitive. I have a spare few minutes at work so might see if I can do it another way.
5. (Original post by aymanzayedmannan)
This standard result is quoted in the formula booklet but would anyone like to have a go at it?

Spoiler:
Show

Obviously wouldn't have been able to think of this without knowing the result already; without further ado:

6. (Original post by Kvothe the arcane)
Spoiler:
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That looks ****ing terrifying
7. (Original post by Dohaeris)
(Original post by Kvothe the arcane)
Spoiler:
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That looks ****ing terrifying
Hey, how so?
8. (Original post by Kvothe the arcane)
Hey, how so?
..
9. (Original post by EricPiphany)
..
Pardon? I couldn't think of another solution. I just ended up with mammoth things which were hard to solve.
10. (Original post by Kvothe the arcane)
Pardon? I couldn't think of another solution. I just ended up with mammoth things which were hard to solve.
I joke.
11. (Original post by Kvothe the arcane)
Hey, how so?
I don't understand it, so I'm afraid of it

Seriously though, kinda ingenious. Not something I would ever be able to do, unfortunately
12. (Original post by Dohaeris)
I don't understand it, so I'm afraid of it

Seriously though, kinda ingenious. Not something I would ever be able to do, unfortunately
Oh, what part? I recognised secx=1/cosx and cosx\cos^2x and used a trig identity.
I then used a substitution.
And then I integrated, resubbed and then did some manipulation.
It's nothing otherworldly and I'm sure you'll be able to do the same thing once you understand .
13. (Original post by Kvothe the arcane)
Oh, what part? I recognised secx=1/cosx and cosx\cos^2x and used a trig identity.
I then used a substitution.
And then I integrated, resubbed and then did some manipulation.
It's nothing otherworldly and I'm sure you'll be able to do the same thing once you understand .
The thing is, looking at the answer, I completely understand it. The problem, as it so often is, is that it comes too late lol. I could look at that question for an hour before deciding that it's some uni ****, but when I look at the answer I slap myself silly for not doing the simpler stuff at least.

This does look like one of those question that are a bit above C4 level, though using C4 material, isn't it? I suppose that's why the answer for it is given in the formula booklet
14. (Original post by Kvothe the arcane)
Spoiler:
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One qualm,

Though that was a typo, nicely done
15. (Original post by Euclidean)
One qualm,

Though that was a typo, nicely done
I've amended but thanks .
16. (Original post by Euclidean)
...
pro tips: to render your brackets correctly with fractions and the like, use \left( and \right)

(Original post by Kvothe the arcane)
I've amended but thanks .
As above; use \cos, \ln, \sin so that you're typesetting functions instead of squashing the variables c, o and s together.
17. (Original post by Zacken)
pro tips: to render your brackets correctly with fractions and the like, use \left( and \right)

As above; use \cos, \ln, \sin so that you're typesetting functions instead of squashing the variables c, o and s together.
Thanks. I always forget to use \ before such functions. Though my lack of proper editing was due to time constraints. I may go back and add aligns etc.
18. (Original post by Zacken)
pro tips: to render your brackets correctly with fractions and the like, use \left( and \right)

Thanks though will do
19. Spoiler:
Show
I've just subbed itself:

Rewriting the integral in terms of u gives us

Note that this is the standard integral for arcosh(u) so I'm quoting it without proof:

by using the logarithmic form of arcosh (again, without proof)

It's a shame no actual C4 students attempted this
20. (Original post by aymanzayedmannan)
Spoiler:
Show
I've just subbed itself:

Rewriting the integral in terms of u gives us

Note that this is the standard integral for arcosh(u) so I'm quoting it without proof:

by using the logarithmic form of arcosh (again, without proof)

It's a shame no actual C4 students attempted this
Wow that's a really good idea

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