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Edexcel A2 C4 Mathematics June 2016 - Official Thread Watch

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    What is meant by produced in vector geometry?

    For example: The line {\vec{OE}} produced meets the line  AB at  F
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    (Original post by NotNotBatman)
    What is meant by produced in vector geometry?

    For example: The line {\vec{OE}} produced meets the line  AB at  F
    From what it seems, I guess it means if you extended (produced) the line OE it would meet the line AB at the point F
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    Quick Question: For question number two on this paper

    https://5c59854d0ccd29d489c9e5e689a8...%20Edexcel.pdf

    How do you know whether to use radians or degrees? I went ahead to use degrees however the mark scheme was in radians? Any help?

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    (Original post by cookiemonster15)
    Quick Question: For question number two on this paper

    https://5c59854d0ccd29d489c9e5e689a8...%20Edexcel.pdf

    How do you know whether to use radians or degrees? I went ahead to use degrees however the mark scheme was in radians? Any help?

    Trig can only be integrated if it's in radians I think
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    (Original post by joodaa)
    Trig can only be integrated if it's in radians I think
    Ah ok, didn't know that.
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    (Original post by joodaa)
    Trig can only be integrated if it's in radians I think
    (Original post by cookiemonster15)
    Ah ok, didn't know that.
    You can only integrate/differentiate trigonometric functions if it is in radians. Basically, all calculus is in radians.

    (NB: you could do it in degrees but you'd need the scaling factors and the taylor series gets all ****ed up, so let's not)
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    (Original post by aymanzayedmannan)
    This is what I got
    Spoiler:
    Show
    \displaystyle v - \ln\left ( v + 4 \right )^{4} = t\left ( \ln^{2}t-2 \ln t + 2 \right )+\mathrm{C}
    :awesome:

    Zacken I tried yours but kept going round in circles so I gave up and went to sleep (well watched a horror move but that's a different story)
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    (Original post by NotNotBatman)
    What is meant by produced in vector geometry?

    For example: The line {\vec{OE}} produced meets the line  AB at  F
    (Original post by kingaaran)
    From what it seems, I guess it means if you extended (produced) the line OE it would meet the line AB at the point F
    Yes but you must extend it past E. If you wanted to go past O it would be described as EO produced.

    An old fashioned word, but very useful.
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    Please can someone explain to me Question 8d from Ex5B

    How is BG = 3b? Should it not be equal to 2b?

    https://e1934e482e1b0d2c8580c3a986eb...EZ3UTQ/CH5.pdf

    Page 20-21. THnak,s
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    (Original post by cookiemonster15)
    Quick Question: For question number two on this paper

    https://5c59854d0ccd29d489c9e5e689a8...%20Edexcel.pdf

    How do you know whether to use radians or degrees? I went ahead to use degrees however the mark scheme was in radians? Any help?

    (Original post by Zacken)
    You can only integrate/differentiate trigonometric functions if it is in radians. Basically, all calculus is in radians.

    (NB: you could do it in degrees but you'd need the scaling factors and the taylor series gets all ****ed up, so let's not)
    I think that it is particularly unkind when this turns up in C2 when you haven't started differentiating or integrating trig functions.
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    (Original post by Mihael_Keehl)
    Please can someone explain to me Question 8d from Ex5B

    How is BG = 3b? Should it not be equal to 2b?

    https://e1934e482e1b0d2c8580c3a986eb...EZ3UTQ/CH5.pdf

    Page 20-21. THnak,s
    Their solution says 2b????
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    (Original post by Mihael_Keehl)
    Please can someone explain to me Question 8d from Ex5B

    How is BG = 3b? Should it not be equal to 2b?

    https://e1934e482e1b0d2c8580c3a986eb...EZ3UTQ/CH5.pdf

    Page 20-21. THnak,s
    The PDF clearly says \vec{BG} = 2b where are you seeing 3b from?

    Edit: ninja-ed.
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    Can someone please help me with connected rates of change. They get me every time. Question 9 of exercise 4E from the heinemann c4 textbook, pls.
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    What topics in C4 do you find the simplest and hardest?

    For me TR is by far the easiest. Beyone the fact it's merely adding numbers together, but you can check the answer on your calculator. Also the follow up Q to most TR Qs are integrating the function anyway..

    I find vectors quite weird, especially the Qs where it's about finding the shortest distance or something like that..
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    (Original post by bat_man)
    Can someone please help me with connected rates of change. They get me every time. Question 9 of exercise 4E from the heinemann c4 textbook, pls.
    Post the Q
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    (Original post by ULTRALIGHT BEAM)
    Post the Q
    Fluid flows out of a cylindrical tank with constant cross section. At time t minutes, t>0, the volume of fluid remaining in the thank is Vm^3. The rate at which the fluid flows in M^3min^-1 is proportional to the sq root of V.
    Show that the depth h metres of fluid in the tank satisfies the differential equation
    dh/dt = -k root h, where k is a positive constant.
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    (Original post by bat_man)
    Fluid flows out of a cylindrical tank with constant cross section. At time t minutes, t>0, the volume of fluid remaining in the thank is Vm^3. The rate at which the fluid flows in M^3min^-1 is proportional to the sq root of V.
    Show that the depth h metres of fluid in the tank satisfies the differential equation
    dh/dt = -k root h, where k is a positive constant.
    Zacken is really good at explaining. Can't understand the Q

    NB: dh/dt = dvdh / dtdv
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    (Original post by ULTRALIGHT BEAM)
    Zacken is really good at explaining. Can't understand the Q

    NB: dh/dt = dvdh / dtdv
    alright thanks anyways bro. And i got dh/dt = dh/dv x dv/dt , right?
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    When working out whether two lines are parallel/skew/intersecting, what is happening geometrically when you solve using the first two equations and get values for lambda and mu but the third equation isn't satisfied? I know that this means I have to say that the lines aren't intersecting but what's going on when I'm doing all of that?

    edit: thinking about it, is it that you've shown a point exists where two of the components are the same but the third component is different on both lines so obvs they don't intersect?
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    (Original post by bat_man)
    alright thanks anyways bro. And i got dh/dt = dh/dv x dv/dt , right?
    Yes
 
 
 
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