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Edexcel A2 C4 Mathematics June 2016 - Official Thread Watch

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    (Original post by Zacken)
    IBP and then the "constant" part cancels out to zero.
    Any idea on how to do part (f)?
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    (Original post by KINGYusuf)
    Any idea on how to do part (f)?
    Sure, I'll get back to you in an hour and a half - have to go out right now.
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    (Original post by KINGYusuf)
    Any idea on how to do part (f)?
    AQR is a straight line so what does tell you about AQ QR ?


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    Hi, does anyone know if there are Solomon worksheets for S1 and S2 ?
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    (Original post by Danllo)
    Hi, does anyone know if there are Solomon worksheets for S1 and S2 ?
    Papers yes, worksheets no.
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    where is everyone up to in their maths revision past paper wise?
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    (Original post by jamessmith15)
    where is everyone up to in their maths revision past paper wise?
    Done all standard past papers, about to move onto the Solomon ones and do extra worksheets on vectors and integration

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    (Original post by blackdiamond97)
    Done all standard past papers, about to move onto the Solomon ones and do extra worksheets on vectors and integration

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    is that for all the units, C3 C4 and m1
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    (Original post by jamessmith15)
    is that for all the units, C3 C4 and m1
    C3 and C4, yes. I do S2, and I've only just started papers on that module
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    Why can't I use the reverse chain rule on (x^2+3)^2 but I can with (x+3)^2 ?
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    (Original post by thad33)
    Why can't I use the reverse chain rule on (x^2+3)^2 but I can with (x+3)^2 ?
    Derivitive inside the bracket is a constant ie 1. Derivitive inside beacket of first one is 2x which you can't divide by using reverse chain rule.


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    (Original post by thad33)
    Why can't I use the reverse chain rule on (x^2+3)^2 but I can with (x+3)^2 ?
    The rule holds when your integral is of the form \int a f'(x)f(x)^{n} \, \mathrm{d}x.
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    (Original post by KINGYusuf)
    Any idea on how to do part (f)?
    Man this isn't even A Level Mathematics ??
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    Hey guys, I'm really struggling with maths, I just sit there in class and in class I understand it but when I do it myself I really don't get it.
    I don't know how and where to start my revision. Last year I didn't work hard enough and I got a D, however I'm retaking a few modules.

    What is the best way for revising for maths? At this point shall I just do past papers and learn the content like that? Will that help me achieve at least a C this year?

    Thank you in advance
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    (Original post by 06052008)
    Hey guys, I'm really struggling with maths, I just sit there in class and in class I understand it but when I do it myself I really don't get it.
    I don't know how and where to start my revision. Last year I didn't work hard enough and I got a D, however I'm retaking a few modules.

    What is the best way for revising for maths? At this point shall I just do past papers and learn the content like that? Will that help me achieve at least a C this year?

    Thank you in advance
    Do one paper. Decide which topics you're not very confident on and go back over notes, online resources etc to increase your understanding. Do another paper. Repeat until your exam.
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    Name:  image.jpg
Views: 82
Size:  258.0 KBOnly for students aiming for 75/75. Will upload answer in 10 mins, soz for handwriting

    A is the point where the tangent meets the X axis
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    thank you!
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    Somebody check my working please, This question was posted way earlier, when I hadn't studied By parts.

    Attempted it now: Would integrating ln^2(x) be expected in C4 though?



    Also someone throw me a nice, By parts question.
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    (Original post by SaadKaleem)
    ...
    Yep, that's fine. Now do

    \displaystyle 

\begin{equation*}\int_0^{2\pi} e^x \cos mx \, \mathrm{d}x = \frac{\alpha}{\beta m^2 + \gamma}(\zeta e^{2\pi} - \mu) \end{equation*}

    Where \alpha, \beta, \gamma, \zeta and \mu are constants to be determined.
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    (Original post by Zacken)
    Yep, that's fine. Now do

    \displaystyle 

\begin{equation*}\int_0^{2\pi} e^x \cos mx \, \mathrm{d}x = \frac{\alpha}{\beta m^2 + \gamma}(\zeta e^{2\pi} - \mu) \end{equation*}

    Where \alpha, \beta, \gamma, \zeta and \mu are constants to be determined.
    Spoiler:
    Show
    \displaystyle \frac{1}{m^{2}+1}\left ( e^{2\pi}-1 \right )?
 
 
 
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