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# P5 Edexcel 21st June - Ack! watch

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1. Hey all.....
p5 was a breeze.... got everything except the last part of question 8(hyperbola)... the locus..... no idea what to do there.....

downside..:.... i spent all my time studying for p5.... i didnt even open p2(which was damn easy.lol)... and i ended up forgetting all the easy stuff.lol.
2. (Original post by infekt)
ok ...igot 6a(sin^2a) .... ... and 24pi(a^2)(u^5 / 5)

u was either cos or sine ... cantremember ...

im totally****ed ... i got eveything rite till q 6 ... then itwas a massacre
Where does sin^2a come from?
i just got 6a for that
3. (Original post by olliemccowan)
yer ur rite - everything was going so well until i hit the last 3 questions and then my life got shattered lol. the woman in the exam was lookin at me very funny when after finishin the 16 page answer booklet i asked for "lots more sheets of paper please".

so annoyed wiv that paper. Anyone who says that it was easy shud be hung, drawn and quartered for lying.
i was getting cold shivers doing the bloody thing ..
4. (Original post by keisiuho)
Where does sin^2a come from?
i just got 6a for that
i got it wrong ... dont bother .... no chance ill get more than 70/100 in this paper ...

gotta do real well in p4 and p6 now
5. (Original post by keisiuho)
Where does sin^2a come from?
i just got 6a for that
yeah thats right.....
do u remember what u got for the area?
6. q.6 - for those interested.

a) ds/dp = 3a sec^3 p tan p.

So dy/dp = dy/ds . ds/dp = 3a sec^3 p tan p . sin p = 3a tan^2 p . sec^2p.

b) Likewise using dx/dp = 3 a sec^2 p tan p gives x = 3/2 a tan^2 p.

c) Drops out like a glove
7. (Original post by beauford)
q.6 - for those interested.

a) ds/dp = 3a sec^3 p tan p.

So dy/dp = dy/ds . ds/dp = 3a sec^3 p tan p . sin p = 3a tan^2 p . sec^2p.

b) Likewise using dx/dp = 3 a sec^2 p tan p gives x = 3/2 a tan^2 p.

c) Drops out like a glove
Same as me, I like intrinsic coordinates
8. I thought it was all ok-ish, but I used long methods on a couple of the questions which meant I didn't have much time to check - the normal to the hyperbola I used the quadratic formula instead of just the sum of the roots, and for the reduction formula I did integration by parts on In, but apparently n*In + (n-1)I(n-2) simplified to the integral from part (a) so you could just do that between the limits and get sqrt2.
9. (Original post by [_Z_])
yeah thats right.....
do u remember what u got for the area?
12a^2pi/5
10. I didn't think it was too bad, but there were a few questions i couldn't do, but hopefully only 10 marks worth or something. I got most of the answers that people have agreed on too . *dances*
11. Totally agreed about it being a messy paper. No harder integration which I'd practised and practised, but loadsa messy algebra which I'd just hoped wouldn't come up. Stupid paper and the reduction formula was the least nice that's been on any of the past papers I'd looked at and GRRRR. Oh well - let's hope P6 is a mislabled p3 paper
12. (Original post by Llamas)
I think that question went something like this:

t= ln3

x = Cosh(t) - t

dx = Sinh(t) - 1
d2x = Cosh(t)

y = Cosh(t) + t

dy = Sinh(t) + 1
d2y = Cosh(t)

dx = 1/3
d2x = 5/3

dy = 7/3
d2y = 5/3

Radius of Curvature = (dx^2 + dy^2)^3/2 / (dx*d2y - dy*d2x)

= (1/9 + 49/9)^(3/2) / (5/9 - 35/9)
= (50/9)^(3/2) / (-30/9)
= (50^(3/2) / 27) / (-30/9)

= -(50^(3/2) / 90)

I think that's right, anyway.
i got the same as this. Well, what i mean is i go (-3/5) x (25/9)^3/2which works out to the same answer when you plug it into a calculator.
13. can anyone please tell me how many marks the following questions were worth:

Intrinsic Co-ordinates

Reduction Formula

Question 8 (rectangular hyperbola)

Thanks
14. (Original post by sam99)
i got the same as this. Well, what i mean is i go (-3/5) x (25/9)^3/2which works out to the same answer when you plug it into a calculator.
But you've got to simplify it
the simplified is 25 root(2)/9
15. Ah~~~~~, did anyone get -ln2 for question 1 b)?

The area in 7 was either (12pi a^2 )/5 or 24 pi a^2 /5. can't remember.

It was a paper on the hard side I think. I got nervous just before I went into the examination. It went ok. So far looking at the answers here, I got all of them correct.

What do you lot reckon the average for P5 is going to be this year? I think 45/75.
16. i feel really sorry 4 u all doing P5 *hugs every1 doing P5*
17. (Original post by keisiuho)
But you've got to simplify it
the simplified is 25 root(2)/9
thye wont cut marks coz i wrote 5root50 / 9 will they ?

if they do im gonna get so screwed ...

oh btw ... if u get 4 out of 6 a's in the 6 module a level course .... p1-p3 god willing all 95+ .... is there a chance of an overall A ?
18. (Original post by sam99)
can anyone please tell me how many marks the following questions were worth:

Intrinsic Co-ordinates

Reduction Formula

Question 8 (rectangular hyperbola)

Thanks

anyone??? i'm really desperate to know. Please! (Even if you are not sure you're correct)
19. (Original post by Camford)
Ah~~~~~, did anyone get -ln2 for question 1 b)?

The area in 7 was either (12pi a^2 )/5 or 24 pi a^2 /5. can't remember.

It was a paper on the hard side I think. I got nervous just before I went into the examination. It went ok. So far looking at the answers here, I got all of them correct.

What do you lot reckon the average for P5 is going to be this year? I think 45/75.
I got -ln2 too. I made a stupid mistake on the surface area (can't remember my answer anyway) - I saw it was only rotated pi about x-axis so halved it, but I forgot about the bottom line rotating as well so rotating the top by 2pi is the same as rotating the whole thing by pi.
20. (Original post by sam99)
anyone??? i'm really desperate to know. Please! (Even if you are not sure you're correct)
I think intrinsic and reduction Qs are worth about 8 or 9 marks each, the hyberbola one was worth up to 14 or so I think. I'll be getting a copy of the paper soon, I'll post it all then.

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