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Copper complex ion with ethandioate and water Watch

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    Hi, can somebody find me a diagram of how a copper ion looks like with 2 water ligands and 2 ethanedioate ligands, I cant seem to find one! Is it an approximately tetrahedral shape, or is it approximately octahedral because ethanedioate is a bidentate ligand?

    Also, when potassium K2 is counterbalancing the negativity, how would you add this to the diagram? Just outside the brackets with its charge?

    Thank you!
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    It is octahedral, and can show cis/trans isomerism too.

    You won't ever be expected to show the K+ ions. They'll always be spectators.
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    (Original post by sumeyyatontus)
    Hi, can somebody find me a diagram of how a copper ion looks like with 2 water ligands and 2 ethanedioate ligands, I cant seem to find one!

    Thank you!
    I can draw it out for you if you think that'd help?

    Octahedral, as ethanedioate is bidentate as you've said (each O- on the ethanedioate ion can form a coordinate bond with Copper), so it has a coordination number of 6
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    Here you go:

    Please excuse my pathetic drawing

    Name:  1454190791058-1168114636.jpg
Views: 116
Size:  496.5 KB
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    (Original post by Neuth)
    Here you go:

    Please excuse my pathetic drawing

    Name:  1454190791058-1168114636.jpg
Views: 116
Size:  496.5 KB
    Thank you so much for this! Better than anything I could have done haha. X
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    (Original post by sumeyyatontus)
    Thank you so much for this! Better than anything I could have done haha. X
    You're welcome!
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    (Original post by Neuth)
    Here you go:

    Please excuse my pathetic drawing

    Name:  1454190791058-1168114636.jpg
Views: 116
Size:  496.5 KB
    Hi Neuth,

    Thanks for the really helpful drawing.

    What would the trans-isomer look like?

    Also, how do you know the ion has a charge of 2-?

    Jasmine
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    (Original post by jasminetwine)
    Hi Neuth,

    Thanks for the really helpful drawing.

    What would the trans-isomer look like?

    Also, how do you know the ion has a charge of 2-?

    Jasmine
    The water ligands would be 180 degrees from each other, like this:
    Name:  IMG_20160131_112809.jpg
Views: 94
Size:  504.4 KB

    You can calculate the charge on a complex ion by adding the charges of the transition metal and ligands together. In this example, Cu is 2+, water is neutral and ethanedioate is 2-.
    2 + 2(-2) = - 2, so the charge is 2-.

    Understand?
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    (Original post by Neuth)
    The water ligands would be 180 degrees from each other, like this:
    Name:  IMG_20160131_112809.jpg
Views: 94
Size:  504.4 KB

    You can calculate the charge on a complex ion by adding the charges of the transition metal and ligands together. In this example, Cu is 2+, water is neutral and ethanedioate is 2-.
    2 + 2(-2) = - 2, so the charge is 2-.

    Understand?
    Yes! I understand. Thank you so much for your clear explanation.

    I have one more question, if you don't mind

    Could you please explain to me optical isomers for complex ions? I'm finding it little hard to visualise.
 
 
 
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