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OCR Mathematics UMS Watch

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    So I did a OCR Core 2 June 2006 paper and got 68/72.
    53 is required for an A
    45 is required for a B

    How many marks would you need for 100 UMS, and how do you work this out?

    Thanks
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    (Original post by SGHD26716)
    So I did a OCR Core 2 June 2006 paper and got 68/72.
    53 is required for an A
    45 is required for a B

    How many marks would you need for 100 UMS, and how do you work this out?

    Thanks
    Check out their website. OCR posts their grade boundaries and UMS conversions year by year online
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    (Original post by Nirvana27)
    Check out their website. OCR posts their grade boundaries and UMS conversions year by year online
    The grade boundaries aren't there for June 2006. I know the grade boundaries from a separate source, which doesn't say for 100 UMS.

    Surely in maths 100 UMS can't only be achieved by 100%
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    (Original post by SGHD26716)
    The grade boundaries aren't there for June 2006. I know the grade boundaries from a separate source, which doesn't say for 100 UMS.

    Surely in maths 100 UMS can't only be achieved by 100%
    I know some girl who thought she got full marks on Core 3 last year cause she got 100 UMS but it turned out she got 71/72
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    (Original post by SGHD26716)
    The grade boundaries aren't there for June 2006. I know the grade boundaries from a separate source, which doesn't say for 100 UMS.

    Surely in maths 100 UMS can't only be achieved by 100%
    Really depends how hard the exam was that year/ how well everyone did. I've had maths exams in which anything from 93%-100% raw marks is 100UMS
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    (Original post by kieran12321LFC)
    I know some girl who thought she got full marks on Core 3 last year cause she got 100 UMS but it turned out she got 71/72
    What I am basically saying is how to work out the boundary for 100 UMS.

    53 is an A
    72-53 = 19

    Therefore, 19 marks make up 20 UMS in the A bracket.
    So 1 mark = 1.05 UMS
    That gives me a UMS of 96 since I got 68/72, which is 15 marks above boundary, 80+ 15(1.05.... =96
 
 
 
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